Question

The vertices of triangle PQR are given in the standard (x,y) coordinate plane below. What is the area, in the square coordinate units, of triangle PQR?

Answer 1

Answer:

Area = 12

Step-by-step explanation:

Given

See attachment

Required

Area of $\triangle PQR$

From the attached image, we have:

$P = (6,10)$

$Q = (10,8)$

$R = (6,4)$

The area is then calculated as:

$A = \frac{1}{2}|(x1y2 - x2y1) + (x2y3 - x3y2) + (x3y1 - x1y3)|$

So, we have:

$A = \frac{1}{2}|(6*8 - 10*10) + (10*4 - 6*8) + (6*10 - 6*4)|$

Using a calculator:

$A = \frac{1}{2}|-24|$

Remove absolute bracket

$A = \frac{1}{2} * 24$

$A = 12$