What is the perimeter, P, of a rectangle that has a length of x +8 and a width of y - 1?
1 answer:
Answer:
P=2x+2y+14
Step-by-step explanation:
Perimeter (P)of a rectangle = 2( l+b)
where l is the length and b is the width of the rectangle .
Here, l= x+8
and, b= y-1
so, P = 2{(x+8)+(y-1)}
= 2( x+8+y-1)
= 2(x+y+7)
=2x+2y+14
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