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2 years ago

What is the perimeter, P, of a rectangle that has a length of x +8 and a width of y - 1?

Mathematics

1 answer:

Dafna1 [17]2 years ago

5 0

Answer:

P=2x+2y+14

Step-by-step explanation:

Perimeter (P)of a rectangle = 2( l+b)

where l is the length and b is the width of the rectangle .

Here, l= x+8

and, b= y-1

so, P = 2{(x+8)+(y-1)}

= 2( x+8+y-1)

= 2(x+y+7)

=2x+2y+14

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<h2>Explanations:</h2>

From the given question, we have the following parameters

Cost of a small greeting card = $1.60

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