2 years ago

PLEASE HELP!!!

Mathematics

1 answer:

frozen [14]2 years ago

3 0

[tex]\dfrac{\dfrac{r-5}{9r}}{\dfrac{5-r}{3r^2}}=\dfrac{r-5}{9r}.\dfrac{-3r^2}{r-5}=\dfrac{-r}{3}[\tex]

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