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UkoKoshka [18]
2 years ago
14

PLEASE HELP!!!

Mathematics
1 answer:
frozen [14]2 years ago
3 0

[tex]\dfrac{\dfrac{r-5}{9r}}{\dfrac{5-r}{3r^2}}=\dfrac{r-5}{9r}.\dfrac{-3r^2}{r-5}=\dfrac{-r}{3}[\tex]

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Answer:

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3 0
3 years ago
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