Answer:
b^1 will be the answer
Step-by-step explanation:
b^5/b^4
b^5-b^4=b^1
Answer:
∠A=26º
∠B=137º
∠C=17º
Step-by-step explanation:
We can use the Law of Cosines because we have all 3 side lengths.
cosA =
cosA=28^2+12^2-18^2 / 2(28)(12)
cosA=604/672
cos-1(604/672
angle A ≈ 26º
cosB =
cosB=-316/432
cos-1(-316/432
angle B ≈ 137º
26+137=163
180-163=17
angle C ≈ 17º
Answer:
Step-by-step explanation:
Column 1 :
Column 2 :
Eqn(1)
Column 3 :
Add the equations.
<u>Fourth column : </u>
<u>Fift column :</u>
<u>Six</u><u>t</u><u>h column :</u>
Substitute .
Hence solution is .
Answer:
1) 35 gallons by the first car 2) 40 gallons by the second car
Step-by-step explanation:
Suppose the first car used x gallons, when the second car used the rest- 75-x
If the first car's efficiency is 35 miles per galon, its milleage is 35*x, the second car's milleage is 15*(75-x). And the summary milleage is equal to 1825.
35x+15(75-x)=1825
35x+1125-15x= 1825
20x=700
x=35- gallons consumed by the first car,
75-35=40- gallons consumed by the second one
Here is the answer to the given problem above. Given that the business owes $8000 on a loan and every month, it pays 1212. So for the first month, the remaining is 6,788. On the second month is 5,576, and on the third month, it is 4,364. In the fourth month, the remaining would be 3,152, and in the fifth month is 1,940. Therefore, on the sixth month, if the business pays 1,212 still, the remaining would be $728 only. Hope this answer helps.