What is the distance between the points (6, -2) and (6, -5)?

Need help ASAP please

Rom4ik [11]

Answer:

What do you need help with?

Step-by-step explanation:

5 0

4 years ago

Answer the question below

posledela

It will take 24 minutes until all of them reach the start at the same time.

6 0

3 years ago

The selling price of an item is $480. It is marked down by 10%, but this sale price is still marked up from the cost of $. Fi

erma4kov [3.2K]

Answer:

Markup = [(Revenue – COGS) / COGS] X 100.

Markup = (Gross Profit / COGS) X 100.

Markup = [(Revenue – COGS) / COGS] X 100.

Markup = [($400 – $250) / $250] X 100.

Selling Price = [(Markup X COGS) + COGS] X 100.

Selling Price = (Markup X COGS) + COGS.

Selling Price = (0.50 X $100) + $100.

Step-by-step explanation:

um i think this is the answer

4 0

3 years ago

Read 2 more answers

Ms kaimal prints out address labels on 3 sheets of paper each sheet is entirely covered in labels each label takes up 1/12 of a

RoseWind [281]

Answer:

Labels did she print is 36.

Step-by-step explanation:

Given : Ms kaimal prints out address labels on 3 sheets of paper each sheet is entirely covered in labels each label takes up $\frac{1}{12}$ of a sheet.

To find : How many labels did she print ?

Solution :

$\frac{1}{12}$ of a sheet takes up 1 label.

So, 1 of a sheet takes up $\frac{1}{\frac{1}{12}}$ label.

1 of a sheet takes up 12 label.

Then, 3 of a sheet takes up $12\times 3$ label.

3 of a sheet takes up 36 label.

Therefore, Labels did she print is 36.

6 0

3 years ago

Read 2 more answers

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago