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3 years ago

Marsha heard that 15% of her algebra class failed.If there were 20 students in the class, how many did not pass?

Mathematics

2 answers:

Strike441 [17]3 years ago

8 0

3 students did not pass.

Kryger [21]3 years ago

4 0

3 students didn’t pass. Explanation- 20x0.15=3

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An arts academy requires there to be 4 teachers for every 84 students and 3 tutors for every 30 students. How many students does

Sonja [21]

Answer:

21 students per teacher

10 students per tutor

10 tutors needed for 110 students

Step-by-step explanation:

84 ÷4=21

30÷3=10

110÷10=10

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3 years ago

spencer spent 4 hours doing chores over the weekend. If he spent 2/3 for an hour on each chore, how many chores did he do.

Elina [12.6K]

2/3 + 2/3 + 2/3 + 2/3
8/3
2 2/3

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3 years ago

Pls help me out in finding the right answers

Mila [183]

The answers are 1, 2, 5, and 7

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3 years ago

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

3 0

3 years ago

Don’t know the answer to this question???

Eva8 [605]

9514 1404 393

Answer:

(b) 9

Step-by-step explanation:

The product of segment lengths to the near and far intersection with the circle is the same for both secants.

4(4+5) = 3(3+x) . . . . the above statement with numbers filled in

36 = 9 +3x . . . . . . . simplify

12 = 3 +x . . . . . . . . divide by 3

9 = x . . . . . . . . . . . subtract 3

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3 years ago