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NemiM [27]
3 years ago
15

Find x so the distance between (x, 2) and (2, 4) is the square root of 13. How do you work this?

Mathematics
1 answer:
kap26 [50]3 years ago
4 0
d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}  \\  \\  \sqrt{13} =  \sqrt{(2-x_1)^2+(4-2)^2}  \\  \\  \sqrt{13} =  \sqrt{(2-x_1)^2+(2)^2}  \\  \\  \sqrt{13} =  \sqrt{(2-x_1)^2+4}  \\  \\  \sqrt{13} =  \sqrt{(2-x_1)*(2-x_1)+4}  \\  \\ \sqrt{13} =  \sqrt{4-2x_1-2x_1+(x_1)^2+4} \\  \\ (\sqrt{13})^2 =  (\sqrt{-4x_1+(x_1)^2+8})^2 \\  \\ 13=(x_1)^2-4x_1+8 \\  \\ (x_1)^2-4x_1-5=0 \\  \\ (x_1-5)(x_1+1)=0 \\  \\ x_1=5,x_1=-1

x can either equal 5 or -1
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Given that the numerator and denominator of a fraction are in the ratio of 3 to 5. When the numerator and denominator are both increased by 2, the fraction is equal to \dfrac{2}{3}.  

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