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3 years ago

8

What is the range of this function?Please help

2 answers:

Alchen [17]3 years ago

7 0

Answer:

B

Step-by-step explanation:

The range is all numbers that Y can range from, so looking at the chart we can see that the highest value on the top of the curve that Y reaches is 4. Looking at the very start of the line and the very end of the line, you can see that -inf is definitely in the range of the y values. So, we can write it like this:

-inf<y<=4

which happens to be B

Romashka-Z-Leto [24]3 years ago

3 0

Range here should be option (b)

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<img src="https://tex.z-dn.net/?f=%5Csf%2015%3D2x-9" id="TexFormula1" title="\sf 15=2x-9" alt="\sf 15=2x-9" align="absmiddle" cl

Genrish500 [490]

Answer:

x=12

Step by step explanation:

Step by step explanation:Add 9 to both sides :

15 = 2x - 9

15 + 9 = 2x - 9 + 9

Simplify:

24 = 2x

Divide both sides to get the result:

24 = 2x

24/2 = (2x)/2

Result:

x=12

$\boxed{\sf Answered \: By\: Subhash}$

$\boxed{\sf Good\: luck \: for \: your \:assignment}$

7 0

2 years ago

What is the value represented by the letter A on the box plot of the data?

Aloiza [94]

It would be b because if you take 10 and shusbejsjdhebe

5 0

2 years ago

You start hiking at an elevation that is 80 meters below base camp.

Arte-miy333 [17]

Answer:

You are now 38 m below base camp.

Step-by-step explanation:

Consider the provided information.

You start hiking at an elevation that is 80 meters below base camp.

Now your initial location is 80 m below base camp, that can be represents as: -80

Now you increase your elevation by 42.

So you go up by 42.

In other words, you get the equation -80+42 = -38.

Since a negative value is below the base camp, this means that you are now 38 m below base camp.

6 0

2 years ago

Find the length of the arc of the circular helix with vector equation r(t) = 2 cos t i + 2 sin t j + tk from the point (2, 0, 0)

USPshnik [31]

$\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath+t\,\vec k$

$\implies\vec r'(t)=-2\sin t\,\vec\imath+2\cos t\,\vec\jmath+\vec k$

$\implies\|\vec r'(t)\|=\sqrt{(-2\sin t)^2+(2\cos t)^2+1^2}=\sqrt5$

Then the length of the arc is

$\displaystyle\int_0^{2\pi}\|\vec r'(t)\|\,\mathrm dt=\sqrt5\int_0^{2\pi}\mathrm dt=2\sqrt5\,\pi$

4 0

3 years ago

If f(x) = (1/9)(9^x) what is f(3)

TiliK225 [7]

Answer: The required value of f(3) is 81.

Step-by-step explanation: We are given the following function :

$f(x)=\left(\dfrac{1}{9}\right)9^x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We are to find the value of f(3).

Substituting x = 3 in equation (i), we get

$f(3)\\\\\\=\left(\dfrac{1}{9}\right)\times9^3\\\\=9^2\\\\=81.$

Thus, the required value of f(3) is 81.

8 0

3 years ago

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