Answer:
11, 14, 17, 20
Step-by-step explanation:
An arithmetic sequence has a common difference d between consecutive terms.
Consider 2, 6, 18, 54
6 - 2 = 4, 18 - 6 = 12, 54 - 18 = 36 ← no common difference, not arithmetic
Consider 3, 6, 12, 24
6 - 3 = 3, 12 - 6 = 6, 24 - 12 = 12 ← no common difference, not arithmetic
Consider 11, 14, 17, 20
14 - 11 = 3, 17 - 14 = 3, 20 - 17 = 3 ← common difference of 3, so arithmetic
Consider 7, 11, 13, 18
11 - 7 = 4, 13 - 11 = 2, 18 - 13 = 5 ← no common difference, not arithmetic
The arithmetic sequence is 11, 14, 17, 20
Answer:
1000 / 10 = 100 strikes per second. Now, multiply by 12 to find the number of strikes that occurred. 100 * 12 = 1200 strikes in 12 seconds. Part B: Divide the number of seconds to the number of lightning strikes to find the average rate. 10 / 1000 = 0.1 seconds per strike. Now, multiply by 7250 to find the number of seconds that passed.
Step-by-step explanation:
There are 1000ml in a liter of water, so depending on how many ml the regular bottles or glasses have, do
x=ml in regular bottles or glasses of water
b= how many regular bottles or glasses of water there would be in a liter of water
1000/x=b
Answer:
378 cookies
Step-by-step explanation:
Let total amount of cookies be y
Let amount of cookies in each small box = x
let amount of cookies in each large box = x + 32
Therefore total amount of cookies in 18 small boxes = 18x
Total amount of cookies in 7 large boxes = 7(x+18) = 7x + 126
Fractional amount of cookies in small & large boxes = 1/2 + 3/7 = 13/14
Total amount of cookies in small & large boxes = 18x + 7x + 126 = 25x + 126
Fractional amount of small cookies equals amount of small cookies in 18 boxes.
3/7y = 18x------------------Eqn 1
From eqn above y = 42x
Equating fractional sum & total sum =
25x + 126 = (13/14)y
Upon cross multiplication
350x + 1764 = 13y---------Eqn 2
Substituting y = 42x into equation 2
350x +1764 = 13(42x)
1764 = 546x - 350x
1764 = 196x
x = 9 cookies
Therefore total number of cookies = 42 × 9 = 378 cookies
Not addition, since
and 0 doesn't belong to the set.
Not subtraction, since
.
It is closed under multiplication. The set appears to contain all non-zero multiples of 3.
Not division, since dividing some of the numbers results in rationals which do not belong to the set.
What other operations are you supposed to consider?
