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Readme [11.4K]
3 years ago
13

The dimensions of triangle B are three times the dimensions of triangle A. The area of triangle B is 364.5 cm2.

Mathematics
2 answers:
CaHeK987 [17]3 years ago
8 0
Area of triangle A/Area of triangle B = (1/3)^2
Area of triangle A/364.5 cm^2 = 1/9
Area of triangle A = 1/9×364.5cm^2
=40.5cm^2
Mrac [35]3 years ago
8 0

40.5 on study island

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Graph f(x) =-2x^+16x-30 by factoring to find the solutions, then find the coordinates of the vertex, and the axis of symmetry. I
fredd [130]

Answer:

<em>Observe attached image</em>

<em>Function zeros:</em>

(3, 0), (5, 0)

<em>Vertex:</em>

(4, 2)

<em>Axis of symmetry:</em>

<em>x =4</em>

Step-by-step explanation:

<u>First factorize the function</u>

f (x) = -2x ^ 2 + 16x-30

<em>Take -2 as a common factor.</em>

-2(x ^ 2 -8x +15)

<em>Now factor the expression x ^ 2 -8x +15</em>

You must find two numbers that when you add them, obtain the result -8 and multiplying those numbers results in 15.

These numbers are -5 and -3

Then we can factor the expression in the following way:

f (x) = -2(x-5)(x-3)

<em><u>The quadratic function cuts the x-axis at </u></em><em>x = 3 and at x = 5.</em>

Now we find the coordinates of the vertex.

For a function of the form ax ^ 2 + bx + c the x coordinate of its vertex is:

x = \frac{-b}{2a}

In the function f (x) = -2x ^ 2 + 16x-30

a = -2\\b = 16\\c = 30

<u>Then the vertice is:</u>

x = \frac{-16}{2(-2)}\\\\x = 4

The y coordinate of the symmetry axis is

y = f (4) = -2 (4) ^ 2 +16 (4) -30\\\\y = 2

The axis of symmetry is a vertical line that cuts the parabola in two equal halves. This axis of symmetry always passes through the vertex.

<u>Then the axis of symmetry is the line</u>

x = 4

<u>The solutions and the vertice written as ordered pairs are:</u>

<em>Function zeros:</em>

(3, 0), (5, 0)

<em>Vertex:</em>

(4, 2)

6 0
3 years ago
ABCEDEFGH is a regular octagon. The minimum degree of rotation by which this octagon can map onto itself is . It will take incre
Mrrafil [7]

Answer:

45 or multiples of 45 around the centre of octagon

Step-by-step explanation:

Given that ABCDEFGH is a regular octagon.  i.e. it has 8 sides.

Since regular ocagon, all interior angles would be equal.

Sum of all interior angles of octagon = 2(8)-4 right angles

= 12 right angles

Hence each angle = 12(90)/8 = 135 degrees

Thus the octagon when rotated will take the same shape if vertices interchange also due to the property that all sides and angles are equal

Since each angle is 135 imagine an octagon with one vertex at origin O, and adjacent vertex B on x axis.   OB has to be coincident with BC the next side or the previous side to get it mapped onto itself

The centre will be at the middle with each side subtending an angle of 45 degrees.

Hence if rotation is done around the centre with 45 degrees we will get octagon mapped onto itself.

45, 90, 135 thus multiples of 45

8 0
3 years ago
If I got $5 a week how much money would I have after 3 weeks
tensa zangetsu [6.8K]
You would get $15 in total because 5x3=15.
6 0
3 years ago
Read 2 more answers
Please help me find limit​
cluponka [151]

9514 1404 393

Answer:

  -13/11

Step-by-step explanation:

Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...

  \displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}

4 0
3 years ago
Math question please show work
garik1379 [7]

You calculate this using the Cosine Rule

x^2 = 60.5^2 + 226^2 - 2*60.5*226 cos 39

= 33484.42

x = 182.98

He threw the ball approximately 183 feet.

7 0
3 years ago
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