Are there any other details as to what the numbers are? otherwise there are six possibilities for this
12+54=66
66=6(_+_)
11=(_+_)
1) 0, 11
2) 1, 10
3) 2, 9
4) 3, 8
5) 4, 7
6) 5, 6
Step-by-step explanation:
x-5 < -3
or, x < -3 +5
or, x < 2
Now,
x +8 >2
or, x >2 - 8
or, x >-6
Answer:
Factor this polynomial:
F(x)=x^3-x^2-4x+4
Try to find the rational roots. If p/q is a root (p and q having no factors in common), then p must divide 4 and q must divide 1 (the coefficient of x^3).
The rational roots can thuis be +/1, +/2 and +/4. If you insert these values you find that the roots are at
x = 1, x = 2 and x = -2. This means that
x^3-x^2-4x+4 = A(x - 1)(x - 2)(x + 2)
A = 1, as you can see from equation the coefficient of x^3 on both sides.
Typo:
The rational roots can be
+/-1, +/-2 and +/-4
Step-by-step explanation:
Subtract 3 from each side to isolate the x and you get x=y-3