answer is 25
Step-by-step explanation:
for something like this you need to use the law of sins. First identify all the angles. There is a 90 degree angle and a 59 degree angle and those are clear. the missing angle is = 59 + 90 = 149
since a triangle has 180 degrees in total you say 180 - 149 = 31. the missing angle is 31 degrees. so we give the angles names. angle with 59 degrees will be angle A, 90 will be B and 31 will be C. So now we just give the sides names. let's replace that x with an a since it's across angle A. the side along angle B will be named b and the side along angle C will be named c. so you say:
Sin A/ a (sin A over a) = Sin B/b = Sin C/c
Sin A is what we are looking for so we say
59 degrees over/ x = sin 31 degrees/ 13 (we leave out the 90 degrees since we don't know the side and also we are not interested in it)
now we do cross multiplying.
say x ×sin 31 degrees = 13× sin 59
now divide these by sin 31
x = 13 × sin 59 ÷ 31 = 25
Answer:
y=3x-3
Step-by-step explanation:
all you need to do is get the -3x to the other side of the equal sign
Answer:
30mph
Step-by-step explanation:
Kyle rides his bike 30mph,
15mph x 2hrs = 30 mph.
15 miles per hour x 3 is 30mph total.
Hope this helps!
Answer:
![\large \boxed{\sf \ \ \ \dfrac{\sqrt{4025}-5}{2}=29.22144... \ \ \ }](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5Csf%20%5C%20%5C%20%5C%20%5Cdfrac%7B%5Csqrt%7B4025%7D-5%7D%7B2%7D%3D29.22144...%20%5C%20%5C%20%5C%20%7D)
Step-by-step explanation:
Hello
<u>Let's note the original speed of the car v</u>
it means that in 1 hour he is going v miles
so to go 200 miles it takes ( in hour)
![\dfrac{200}{v}](https://tex.z-dn.net/?f=%5Cdfrac%7B200%7D%7Bv%7D)
If the speed of the car is v+5 than to go 200 miles it takes (in hour)
![\dfrac{200}{v+5}](https://tex.z-dn.net/?f=%5Cdfrac%7B200%7D%7Bv%2B5%7D)
and this time is one hour less so we can write
![\boxed{\sf \ \ \dfrac{200}{v+5}=\dfrac{200}{v}-1 \ \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20%5C%20%5C%20%5Cdfrac%7B200%7D%7Bv%2B5%7D%3D%5Cdfrac%7B200%7D%7Bv%7D-1%20%5C%20%5C%20%7D)
We can multiply by v(v+5) both parts of the equation so
![200v=200(v+5)-v(v+5)\\\\200v=200v+1000-v^2-5v\\\\v^2+5v-1000=0](https://tex.z-dn.net/?f=200v%3D200%28v%2B5%29-v%28v%2B5%29%5C%5C%5C%5C%3C%3D%3E200v%3D200v%2B1000-v%5E2-5v%5C%5C%5C%5C%3C%3D%3Ev%5E2%2B5v-1000%3D0)
![\Delta=b^2-4ac=5^2+4*1000=4025\\\\ \text{There are potential solutions }\\\\\ \ \ \ \ x_1=\dfrac{-5-\sqrt{4025}}{2}\\\\\ \ \ \ \ x_2=\dfrac{-5+\sqrt{4025}}{2}](https://tex.z-dn.net/?f=%5CDelta%3Db%5E2-4ac%3D5%5E2%2B4%2A1000%3D4025%5C%5C%5C%5C%20%5Ctext%7BThere%20are%20potential%20solutions%20%7D%5C%5C%5C%5C%5C%20%5C%20%5C%20%5C%20%5C%20x_1%3D%5Cdfrac%7B-5-%5Csqrt%7B4025%7D%7D%7B2%7D%5C%5C%5C%5C%5C%20%5C%20%5C%20%5C%20%5C%20x_2%3D%5Cdfrac%7B-5%2B%5Csqrt%7B4025%7D%7D%7B2%7D)
Only one is positive and this is is
![x_1=\dfrac{\sqrt{4025}-5}{2}=29.22144...](https://tex.z-dn.net/?f=x_1%3D%5Cdfrac%7B%5Csqrt%7B4025%7D-5%7D%7B2%7D%3D29.22144...)
So the original speed is 29.22144... mph
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Answer:
AC = AB + BC
18 = (2X - 4) + (3X + 2)
18 = 5X - 2 ( add/subtract like terms)
20 = 5X (-2 take over otherside - 18 + 2)
X = 4
SUB X INTO AB AND BC
AB = 2(4) - 4 = 4
BC = 3(4) + 2 = 14