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Dmitrij [34]
2 years ago
8

So I have this question here, can someone please help me?

Mathematics
2 answers:
sergiy2304 [10]2 years ago
4 0

\\ \rm\rightarrowtail tan\theta=\dfrac{Perpendicular}{Base}

\\ \rm\rightarrowtail tan51=\dfrac{x}{10}

\\ \rm\rightarrowtail x=10tan51

\\ \rm\rightarrowtail x=10(1.2348971565350)

\\ \rm\rightarrowtail x=12.348971565350

salantis [7]2 years ago
3 0

Answer:

Use tan trig ratio:

\sf tan(\theta)=\dfrac{O}{A}

where \theta is the angle, O is the side opposite the angle, and A is the side adjacent the angle

Given:

  • \theta = 39°
  • O = 10
  • x = A

Substituting these values into the formula:

\implies  \tan(39)=\dfrac{10}{x}

Multiplying both sides by x:

\implies  x\tan(39)=10

Dividing both sides by \tan(39) :

\implies  x=\dfrac{10}{\tan(39)}

\implies  x=12.34897157...

\implies  x=12.3 \ \textsf{(nearest tenth)}

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\qquad 1.34\cdot 10^{9}\,\cancel{\text{km}^3} \cdot 1.03 \cdot 10^{12}\,\dfrac{\text{kg}}{\cancel{\text{km}^3}} = 1.3802 \cdot 10^{21}\,\text{kg}1.34⋅10

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Hint #2

Next we want to know what portion of the earth's mass this represents. We have:

\qquad \begin{aligned} \dfrac{\text{mass of the oceans}}{\text{total mass of the earth}} &= \dfrac{1.3802 \cdot 10^{21}\,\text{kg}}{6\cdot 10^{24}\,\text{kg}} \\\\ &= \dfrac{1.3802}{6\cdot 10^{3}} \\\\ &= \dfrac{1.3802}{6000} \\\\ &= 0.0002300\overline{3} \end{aligned}

total mass of the earth

mass of the oceans

​

​

 

=

6⋅10

24

kg

1.3802⋅10

21

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​

=

6⋅10

3

1.3802

​

=

6000

1.3802

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=0.0002300

3

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To convert this to a percent, we multiply by 100100100, so the oceans represent 0.02300\overline{3}\%0.02300

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%0, point, 02300, start overline, 3, end overline, percent of the earth's total mass, according to these figures.

Hint #3

To the nearest hundredth of a percent, 0.020.020, point, 02 percent of the earth's mass is from oceans.

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