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Ber [7]
3 years ago
13

Please help me ! Is it 1 or 3

Mathematics
2 answers:
katen-ka-za [31]3 years ago
7 0

Answer:

not Shure but I think it is 1

dsp733 years ago
3 0

Answer:

its 3

Step-by-step explanation:

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Please help me with this
Illusion [34]

Answer:

2x for the first term

The whole thing is 2x+3

Step-by-step explanation:

Think of it like normal division

What will get the closest answer to 2x^2+x?

2x*x-1=2x^2-2x

Now the expression is 3x-3 so if you but 3 than it becomes 3x-3 which would be a remainder of 0

5 0
3 years ago
What is the vertex of r(x) ? Use r(x)=1/2(x+9)(x-5)
IceJOKER [234]

(0, -[\frac{45}{2})

3 0
3 years ago
If f(x)=-8x+8 and g(x) = sqrt x-9 what is (f•g)(18)
Serggg [28]

Answer:

-16

Step-by-step explanation:

f(x)=-8x+8 and g(x) = sqrt x-9

(f•g)(18)=f(g(18))

g(18)=sqrt(18-9)=sqrt9=3

f(3)=-24+8=-16

7 0
3 years ago
10. Which of the following statements are TRUE?
Masja [62]

Answer:

A, C, D

Step-by-step explanation:

1) A triangular pyramid has the same number of faces as vertices: 5

2) C - The sum is 5 + 6 =11

3) D - Euler's Formula tells us that if we add the number of faces and vertices together and then subtract the number of edges, we will get 2 as our answer.

4 0
3 years ago
(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop
zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})

Compute the sample sizes as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}

       n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}

          =\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

\hat p_{1}=0.45\\\hat p_{2}=0.58

Compute the sample size as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}

       n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}

          =\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666

Thus, the sample sizes are 6666.

7 0
3 years ago
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