Answer:
6x² – 10y² + 2xy + 10
Step-by-step explanation:
We'll begin calculating the sum of
x² + 3y² – 6xy and 2x² – y² + 8xy + 8
This can be obtained as follow:
... x² + 3y² – 6xy
+ 2x² – y² + 8xy + 8
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3x² – 2y² + 2xy + 8
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Next, we shall determine the sum of:
–3x² + 4y² + 3 and 4y² – 5
This can be obtained as follow:
–3x² + 4y² + 3
+ 4y² – 5
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–3x² + 8y² – 2
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Finally, we shall subtract the sum of:
–3x² + 4y² + 3 and 4y² – 5
from the sum of:
x² + 3y² – 6xy and 2x² – y² + 8xy + 8
This can be obtained as follow:
.. 3x² – 2y² + 2xy + 8
– (–3x² + 8y² – 2)
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6x² – 10y² + 2xy + 10
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Answer:
64,98*63.98
Step-by-step explanation:
Answer:
The answer is 10.
Step-by-step explanation:
There would be 10 players, 2 for each group, and if each player played every other player twice, then that would mean that 20 matches of chess were played.
Hope this helped!! (:
Answer:
56.42 minutes
Step-by-step explanation:
The initial sample= y0 = 800
After 13 minutes , amount = 320
Y= y0e-kt
320 = 800e-k(13)
320/800 = e-k13
0.4 = e-k13
In0.4 = -k13
-0.91629= -k13
0.07048= k
Y = 800e-0.07048t
Minutes when the bacterial present will be 15
15 = 800e-0.07048t
15/800= e-0.07048t
0.01875 = e-0.07048t
In 0.01875 = -0.07048t
-3.97656 = -0.07048t
-3.97656/-0.07048= t
56.42 = t
56.42 minutes