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2 years ago

Question 7 of 15

Mathematics

1 answer:

elena55 [62]2 years ago

5 0

Answer:

Option D is the correct answer.

Step-by-step explanation:

(2,9) and (2,5) are separated by a distance of 4 units because 9-5 is 4.

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How many cubes with side lengths of \dfrac14\text{ cm}

bogdanovich [222]

Answer:

Step-by-step explanation:

Correct question

How many cubes with side lengths of ¼cm needed to fill the prism of volume 4 cubic units?

We know that,

Volume of a cube is s³

V = s³

Where 's' is length of side of a cube

Given that

The cube has a length of ¼cm, and a cube has equal length

s= ¼cm

Then, it's volume is

V = s³

V = (¼)³ = ¼ × ¼ × ¼

V = 1 / 64 cubic unit

V = 0.015625 cubic unit

Then, given that the volume of the prism to be filled is 4 cubic unit

Then,

As, we have to find the number if cubes so we will divide volume of prism by volume of one cube

Then,

n = Volume of prism / Volume of cube

n = 4 / 0.015625

n = 256

So, then required cubes to filled the prism is 256 cubes.

5 0

2 years ago

Read 2 more answers

Please help!!!!!!!!!!!!!!

Aloiza [94]

Answer:

11.4 feet

Step-by-step explanation:

Using the right triangle formed by the tent pole, the ground and the guy rope, where the guy rope (g) is the hypotenuse.

Applying Pythagoras' identity

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

g² = 9² + 7² = 81 + 49 = 130 ( take the square root of both sides )

g = $\sqrt{130}$ ≈ 11.4 feet

7 0

2 years ago

Need Help with this question

Fantom [35]

82
The sum of the three angles is 180. One is given and the other we can figure out because it forms a straight line (180) with the angle to the left outside. The outside angle is 117, so 180-117 is 63.
So then add up the 3 angles in the triangle
63+35+y=180
y= 82

3 0

2 years ago

Consider the line y=- 2x+7.

iVinArrow [24]

Answer:

the slope is rhe same -2

Step-by-step explanation:

the slope is the opposite +1/2

3 0

2 years ago

Read 2 more answers

1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.

xxTIMURxx [149]

First, rewrite the equation so that y is a function of x :

$x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}$

(If you were to plot the actual curve, you would have both $y=x^{2/3}$ and $y=-x^{2/3}$ , but one curve is a reflection of the other, so the arc length for 1 ≤ x ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

$\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx$

We have

$y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}$

Then in the integral,

$\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx$

Substitute

$u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx$

This transforms the integral to

$\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du$

and computing it is trivial:

$\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)$

We can simplify this further to

$\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}$

7 0

2 years ago