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AlladinOne [14]

3 years ago

10

If $190 is invested at an interest rate of 11% per year and is compounded continuously, how much will the investment be worth in

4 years? Use the continuous compound interest formula: A = Pert.
a. $198.55
b. $209.51
c. $295.01
d. $2,950.14

1 answer:

Eduardwww [97]3 years ago

5 0

Answer:

answer is c) 295.01

hope this helps

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Answer:

Cyrus needs to order 3 full pizzas to feed his 11 friends .

Step-by-step explanation:

The number of friends invited = 11

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Reptile [31]

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3 years ago

Luana bought a new phone and plan. She paid $175. after three months, She paid $295. after 6 months. Write an equation that mode

elixir [45]

Answer: Hence, our required model will be

$C=40m+55$

Explanation:

Since we have given that

Luana bought a new phone and

For 3 months, the amount she paid = $175

For 6 months, the amount she paid = $295

Now, we have to model an equation ,

Here, let cost be 'C' and

Let number of months be 'm'.

So, we will use the "equation of line" i.e. for two point slope form :

Here y represented by 'C' and x represented by 'm'

So,

$C-C_0=\frac{295-175}{6-3}(m-m_0)\\\\C-175=\frac{120}{3}(m-3)\\\\C-175=40(m-3)\\\\C-175=40m-120\\\\C=40m-120+175\\\\C=40m+55$

Hence, our required model will be

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6 0

3 years ago

A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday�s mail. In actuali

Softa [21]

Answer:

P(Y = 0) = 0.09

P(Y = 1) = 0.4

P(Y = 2) = 0.32

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Step-by-step explanation:

Let the events be:

$W =$ Wednesday

$T =$ Thursday

$F =$ Friday

$S =$ Saturday

Their corresponding probabilities are

$P(W) = 0.3\\P(T) = 0.4\\P(F) = 0.2\\P(S) = 0.1$

Since $Y$ = number of days beyond Wednesday that it takes for both magazines to arrive(so possible $Y$ values are 0, 1, 2 or 3)

The possible number of outcomes are therefore $4^2 = 16\\(W, W), (W, T), (W, F), (W, S)\\(T, W), (T, T), (T, F), (T, S)\\(F, W), (F, T), (F, F), (F, S)\\(S, W), (S, T), (S, F), (S, S)$

The values associated for each of the outcomes are as follows:

$Y(W, W) = 0, Y(W, T) = 1, Y(W, F) = 2, Y(W, S) = 3\\Y(T, W) = 1, Y(T, T) = 1, Y(T, F) = 2, Y(T, S) = 3\\Y(F, W) = 2, Y(F, T) = 2, Y(F, F) = 2, Y(F, S) = 3\\Y(S, W) = 3, Y(S, T) = 3, Y(S, F) = 3, Y(S, S) = 3$

The probability mass function of $Y$ is,

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3 years ago

The ordered pair (3,6) is the solution of the system of equations represented by which lines<br>

Temka [501]

Answer:

p and n

Step-by-step explanation:

The solution to a system of equations given graphically is at the point of intersection of the 2 lines.

The lines p and n intersect at (3, 6)

Thus (3, 6) is the solution to the system of equations represented by p and n

8 0

2 years ago