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Tomtit [17]
3 years ago
15

HELP! please answer the question correctly :)

Mathematics
2 answers:
andrew-mc [135]3 years ago
7 0

Answer:

Where's the question

Step-by-step explanation:

MissTica3 years ago
4 0

Answer: The answer is b

Step-by-step explanation:

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A thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F. Af
fgiga [73]

Answer:

53.3324

Step-by-step explanation:

given that a  thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F.

By Newton law of cooling we have

T(t) = T+(T_0-T)e^{-kt}

where T (t) is temperature at time t,T =surrounding temperature = 40, T0 =70 = initial temperature

After half minute thermometer reads 60° F. Using this we can find k

T(0,5) = 40+(70-40)e^{-k/2} = 60\\e^{-k/2} =2/3\\-k/2 = -0.4055\\k = 0.8110

So equation is

T(t) = 40+(30)e^{-0.8110t}\\

When t=1,

we get

T(1) = 40+(30)e^{-0.8110}\\\\=53.3324

5 0
3 years ago
Can y’all help me what do I do here please I’ll give you brainliest
exis [7]

Answer:

1, 2, -3, 51

Step-by-step explanation:

0 ÷ 2 = 0

0 + 1 = 1

2 ÷ 2 = 1

1 + 1 = 2

-8 ÷ 2 = -4

-4 + 1 = -3

100 ÷ 2 = 50

50 + 1 = 51

3 0
3 years ago
Draw the reflected image of ABCD over line l.
Alina [70]

Answer: The second image, the second image where b' is right above b is the correct answer for this, hope this helped!

<!> Brainliest is appreciated! <!>

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Write 6870628 and 18333206 to the nearest thousand​
Mila [183]

The answers are:

6,871,000

and

18,333,000

5 0
3 years ago
Read 2 more answers
If sin theta = 8/17 and cot theta &lt; 0, what is sec theta?
klasskru [66]

Answer:

-\frac{17}{15}

Step-by-step explanation:

By definition, \cot \theta=\frac{1}{\tan \theta} and \sec \theta=\frac{1}{\cos \theta}. Since since \cot \theta is negative, \tan \theta must also be negative, and since \sin \theta is positive, we must be in Quadrant II.

In a right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. The cosine of an angle in a right triangle is equal to its adjacent side divided by the hypotenuse. Therefore, we can draw a right triangle in Quadrant II, where the opposite side to angle theta is 8 and the hypotenuse of the triangle is 17.

To find the remaining leg, use to the Pythagorean Theorem, where a^2+b^2=c^2, where c is the hypotenuse, or longest side, of the right triangle and a and b are the two legs of the right triangle.

Solving, we get:

8^2+b^2=17^2,\\b^2=17^2-8^2,\\b^2=\sqrt{17^2-8^2}=\sqrt{225}=15

Since all values of cosine theta are negative in Quadrant II, all values of secant theta must also be negative in Quadrant II.

Thus, we have:

\sec\theta=\frac{1}{\cos \theta}=-\frac{1}{\frac{15}{17}}=\boxed{-\frac{17}{15}}

6 0
3 years ago
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