If you find the answer let me know please e
the square of b: b^3
three fourths the square of b: (3/4)b^2
7 less than three fourths the square of b: (3/4)b^2 - 7
Answer:
Only choices C and D are solutions
Step-by-step explanation:
6x + 3y = -15
y = -2x - 5
6x + 3y = -15
6x + 3(-2x - 5) = -15
6x - 6x - 15 = -15
0 = 0
Since 0 = 0 is a true statement, both equations of this system are the same equation and represent a single line on the coordinate plane.
We need to check each choice in just one equation.
Let's use the second equation.
y = -2x - 5
A.
(2, 7)
7 = -2(2) - 5
7 = -4 - 5
7 = -9 False
Not a solution
B.
(5, 0)
0 = -2(5) - 5
0 = -10 - 5
0 = -15 False
Not a solution
C.
(-3, 1)
1 = -2(-3) - 5
1 = 6 - 5
1 = 1 True
Solution
D.
-13 = -2(4) - 5
-13 = -8 - 5
-13 = -13 True
Solution
Answer: Only choices C and D are solutions
Steps to solve:
-1/2 + (3/4 * 4/9)
~Simplify
-1/2 + 14/36
~Simplify
-1/2 + 7/18
~Find common denominators
-9/18 + 7/18
~Add
-2/18 or -1/9
Best of Luck!
