Answer:
53.3324
Step-by-step explanation:
given that a thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F.
By Newton law of cooling we have
T(t) = 
where T (t) is temperature at time t,T =surrounding temperature = 40, T0 =70 = initial temperature
After half minute thermometer reads 60° F. Using this we can find k

So equation is

When t=1,
we get

Answer:
1, 2, -3, 51
Step-by-step explanation:
0 ÷ 2 = 0
0 + 1 = 1
2 ÷ 2 = 1
1 + 1 = 2
-8 ÷ 2 = -4
-4 + 1 = -3
100 ÷ 2 = 50
50 + 1 = 51
Answer: The second image, the second image where b' is right above b is the correct answer for this, hope this helped!
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Step-by-step explanation:
Answer:

Step-by-step explanation:
By definition,
and
. Since since
is negative,
must also be negative, and since
is positive, we must be in Quadrant II.
In a right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. The cosine of an angle in a right triangle is equal to its adjacent side divided by the hypotenuse. Therefore, we can draw a right triangle in Quadrant II, where the opposite side to angle theta is 8 and the hypotenuse of the triangle is 17.
To find the remaining leg, use to the Pythagorean Theorem, where
, where
is the hypotenuse, or longest side, of the right triangle and
and
are the two legs of the right triangle.
Solving, we get:

Since all values of cosine theta are negative in Quadrant II, all values of secant theta must also be negative in Quadrant II.
Thus, we have:
