Answer:
The probability that a randomly chosen code starts with M and ends with E is 0.05 ....
Step-by-step explanation:
According to the given statement we have to make five letter code from A, F, E, R, and M without repeating any letter. We have to find that what is probability that a randomly chosen code starts with M and ends with E.
Thus the probability of picking the first letter M = 1/5
After that we require the sequence (not E, not E, not E) which is equal to:
= 3/4 * 2/3* *1/2
= 1/4
Now multiply 1/5 and 1/4
1/5 * 1/4
= 1/20
= 0.05
Therefore the probability that a randomly chosen code starts with M and ends with E is 0.05 ....
Answer:
150 is the answer. Im not hawt at all :P
Step-by-step explanation:
180 - 30 = 150
lol i remember that iready
Length of x is 98.2 m
<u>Step-by-step explanation:</u>
Step 1:
Use the trigonometric ratio tan 27° to find the common side of both the right angled triangles.
tan 27° = opposite side/adjacent side = opposite side/9
∴ Opposite side = 9 tan 27° = 9 × - 3.27 = -29.46 m
Step 2:
Use this side and trigonometric ratio cosine to find the value of x.
cos 49° = adjacent side/x = -29.46/x
∴ x = -29.46/cos 49° = -29.46/0.30
= 98.2 m (negative value neglected)
Answer:
x = 43/12
y = - 35/6
Step-by-step explanation:
4x + 4y = -9
y = 2x - 13
4x + 4(2x - 13) = - 9
4x + 8x - 52 = - 9
12x = 52 - 9
12x = 43
x = 43/12
y = 2×43/12 - 13
y = 86/12 - ¹²⁾13
y = (86 - 156)/12
y = - 70/12
y = - 35/6
Answer:
80
Step-by-step explanation
Well every triangle has to equal 180 degrees.
So you would add the two degrees you already have, which on this one you would get 100.
Then, you would subtract that number from 180 to get 80.
Hope this helps you!!
