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Elanso [62]
2 years ago
8

Cookies are on sale! Today each cookie costs \$0.75$0.75dollar sign, 0, point, 75 less than the normal price. Right now if you b

uy 777 of them it will only cost you \$2.80$2.80dollar sign, 2, point, 80!Write an equation to determine the normal price of each cookie
Mathematics
2 answers:
TEA [102]2 years ago
8 0

Answer:

The equation to determine the normal price of each cookie is

7(x - 0.75) = 2.80

The normal price of each cookie = $1.15

Step-by-step explanation:

Let us represent the normal price of a cookie as : x

We are told that:

Today each cookie costs \$0.75less than the normal price.

The price of a cookie today is

x - 0.75

Right now if you buy 7 of them it will only cost you \$2.80$

Hence:

7(x - 0.75) = 2.80

Solving for x

7x - 5.25 = 2.80

7x = 2.80 + 5.25

7x = 8.05

x = 8.05/7

x = $1.15

The normal price of each cookie = $1.15

LiRa [457]2 years ago
4 0

Answer:

$ 1.15

Step-by-step explanation:

7(c-0.75) = 2.80 is the equation

$1.15 is the total for C

I did this khan before and this is correct

Hope this helps!

;)

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Kala purchased a prepaid phone card for $30. Long distance calls cost 9 cents a minute using this card. Kala used her card only
Romashka [77]

Answer:

The call lasted 13 minutes

Step-by-step explanation:

In this question, we are told to find the number of minutes a call lasted.

The initial amount on the card is $30 and after making a phone call just once, the balance went down to $28.83

What was used would be 30 - 28.83 = $1.17 or simply 117 cents

Now these long calls come at a cost of 9 cents per minute and we have a total of 117 cents here; the number of minutes is thus 117/9 = 13

This means Kala spent 13 minutes on the call

8 0
3 years ago
Read 2 more answers
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timama [110]

Use the change-of-basis identity,

\log_x(y) = \dfrac{\ln(y)}{\ln(x)}

to write

xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}

Use the product-to-sum identity,

\log_x(yz) = \log_x(y) + \log_x(z)

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and simplify to

xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)

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xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}

Simplify and rewrite using the logarithm properties mentioned earlier.

xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1

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xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}

xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)

\implies \boxed{xyz = x + y + z + 2}

(C)

6 0
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8_murik_8 [283]


well the quotient means the answer to a division, so in this case:

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Answer:

Step-by-step explanation:

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