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Answer:
60 times will they ring together at the same second in one hour excluding the one at the end.
Step-by-step explanation:
Given : Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively.
To find : How many times will they ring together at the same second in one hour excluding the one at the end?
Solution :
First we find the LCM of 3, 6, 10, 12 and 15.
2 | 3 6 10 12 15
2 | 3 3 5 6 15
3 | 3 3 5 3 15
5 | 1 1 5 1 5
| 1 1 1 1 1
So, the bells will ring together after every 60 seconds i.e. 1 minutes.
i.e. in 1 minute they rand together 1 time.
We know, 1 hour = 60 minutes
So, in 60 minute they rang together 60 times.
Therefore, 60 times will they ring together at the same second in one hour excluding the one at the end.
Answer: $9 per hour at his job as a cashier and $8 per hour at his job delivering newspapers.
Step-by-step explanation:
1. Let's call the amount he got paid per hour at his job as a cashier: .
Let's call the amount he got paid per hour at his job delivering newspapers: .
2. Keeping on mind the information given in the problem above, you can make the following system of equations:
3. You can solve it by applying the Substitution method, as following:
- Solve for one of the variables from one of the equations and substitute it into the other equation to solve for the other variable and calculate its value.
- Substitute the value obtained into one of the original equations to solve for the other variable and calculate its value.
4. Therefore, you have:
Then:
Finally:
Therefore he got paid $9 per hour at his job as a cashier and $8 per hour at his job delivering newspapers.