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My name is Ann [436]
3 years ago
6

The following graph describes function 1, and the equation below it describes function 2. Determine which function has a greater

maximum value, and provide the ordered pair.
Function 1 graph of function f of x equals negative x squared plus 8 multiplied by x minus 15 Function 2 f(x) = −x2 + 2x − 3
Function 1 has the larger maximum at (1, 4).
Function 1 has the larger maximum at (4, 1). Function 2 has the larger maximum at (1, −2).
Function 2 has the larger maximum at (−2, 1).
Mathematics
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

A.) Function 1 has the larger maximum at (4, 1).

Step-by-step explanation:

No step-by-step explanation, nobody pays attention to them anyway.

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grandymaker [24]

We have been given graph of a downward opening parabola with vertex at point (6.5,42.25). We are asked to write equation of the parabola in standard form.

We know that equation of parabola in standard form is f(x)=ax^2+bx+c.

We will write our equation in vertex form and then convert it into standard form.

Vertex for of parabola is y=a(x-h)^2+k, where point (h,k) represents vertex of parabola and a represents leading coefficient.

Since our parabola is downward opening so leading coefficient will be negative.

Upon substituting coordinates of vertex and point (0,0) in vertex form, we will get:

0=-a(0-6.5)^2+42.25

0=-a(42.25)+42.25

-42.25=-a(42.25)+42.25-42.25

-42.25=-42.25a

a=1 Divide both sides by -42.25

So our equation in vertex form would be f(x)=-(x-6.5)^2+42.25.

Let us convert it in standard from.

f(x)=-(x^2-13x+42.25)+42.25

f(x)=-x^2+13x-42.25+42.25

f(x)=-x^2+13x

Therefore, the equation of function is standard form would be f(x)=-x^2+13x.

3 0
4 years ago
Tickets to a school play are $4.50 for an adult and $3.00 for a student. If 300 tickets are sold and $1087.50 collected, how man
Kryger [21]

Answer:

<h2>125 tickets for an adult</h2><h2>and 175 tickets for a student</h2>

Step-by-step explanation:

a-\text{number of the tickets for an adult}\\s-\text{number of the tickets for a student}\\\\(1)\qquad a+s=300\\(2)\qquad4.5a+3s=1087.5\\------------\\(1)\\a+s=300\qquad\text{subtstitute}\ s\ \text{from both sides}\\a=300-s\\\\\text{Put it to (2):}\\\\4.5(300-s)+3s=1087.5\qquad\text{use distributive property}\\\\(4.5)(300)+(4.5)(-s)+3s=1087.5\\\\1350-4.5s+3s=1087.5\qquad\text{subtract 1350 from both sides}\\\\-1.5s=-262.5\qquad\text{divide both sides by (-1.5)}\\\\\boxed{s=175}

\text{Put the value of}\ s\ \text{to (1):}\\\\a=300-175\\\\\boxed{a=125}

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ivanzaharov [21]

Step-by-step explanation:

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Answer:

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7 0
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