Answer:
none
Step-by-step explanation:
We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.
According to the 'Law of Sines- Ambiguous Case', we have,
If a < b×sinA, then no triangle is possible.
If a = b×sinA, only one triangle is possible
If a > b×sinA, two triangles are possible.
So, we have,
b×sinA = 10 × sin30 = 10 × 0.5 = 5.
Now, as
4 = a < bsinA = 5.
We get, according to the rule, no triangle is possible.
Answer:
10y^2-3xy+6x
Step-by-step explanation:
Actually you can't solve this. There is no solutions.
Step-by-step explanation:
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8f+37 is the answer to check:
4 times 8 is 32 + 4 times 2f is 8f..........then 32+8f+5 to 8f + 37 is your answer
