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svetlana [45]
3 years ago
11

Required that there must be chaperones for every 25 how many chaperones must there be for 80 students

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
3 0

Answer:

6 chaperones on 80 students.

Step-by-step explanation:

Here is the complete question: School guideline required that there must be 2 chaperones for every 25 students on a school trip. how many chaperones must there be for 80 students?

Given: There must be 2 chaperones on every 25 students.

       

Now, we will use unitary method to solve.

We know 2 chaperones = 25 students

∴ one student required \frac{2}{25}\ chaperones

Next for 80 students, we require= \frac{2}{25} \times 80 = \frac{160}{25}

∴ For 80 students, we require 6.4 \ chaperones, however, we cannot use decimal for number of person, so we can round off the number to 6 chaperones on every 80 students.

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Pavel [41]

Answer:

9cups of dried split peas

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3 cups of chopped onion

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Step-by-step explanation:

The recipe serves 8 people, so to figure out how much you need to serve 32 people you multiply each measurment by 4 because 8 x 4=32.

2 1/4 x 4 = 9

2 x 4 = 8

3/4 x 4 = 3

1 x 4 = 4

2 x 4 = 8

6 0
3 years ago
What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where
Setler79 [48]

Answer:

k=-16,k=-8,k=8,k=16

Step-by-step explanation:

We are given quadratic equations as

x^2+kx+15

and it can be factored as

=(x+a)(x+b)

now, we can multiply factor term

(x+a)(x+b)=x^2+(a+b)x+ab

now, we can compare

x^2+(a+b)x+ab=x^2+kx+15

so, we get

k=a+b

ab=15

we are given that

'a' and 'b' are integers

so, we can find all possible factors

15=(-1\times -15),(1\times 15)

15=(-3\times -5),(3\times 5)

so, we can find k

At (-1\times -15):

k=a+b

we can plug values

k=-1-15

k=-16

At (1\times 15):

k=a+b

we can plug values

k=1+15

k=16

At (-3\times -5):

k=a+b

we can plug values

k=-3-5

k=-8

At (3\times 5):

k=a+b

we can plug values

k=3+5

k=8

So, values of k are

k=-16,k=-8,k=8,k=16

6 0
3 years ago
GIVING 100 POINTS!!!!
IrinaK [193]

Answer:

As per dot plots we see the distribution of prices is close but majority of prices are concentrated in different zones. So MAD would be more similar by the look.

<u>Let's verify</u>

<h3>Neighborhood 1</h3>

<u>Data</u>

  • 55, 55, 60, 60, 70, 80, 80, 80, 90, 120

<u>Mean</u>

  • (55*2+ 60*2+ 70+ 80*3 + 90+ 120)/10 = 75

<u>MAD</u>

  • (20*2+15*2+5+5*3+15+45)/10 = 15
<h3>Neighborhood 2</h3>

<u>Data</u>

  • 100, 110, 110, 110, 120, 120, 120, 140, 150, 160

<u>Mean</u>

  • (100 + 110*3+ 120*3+ 140 + 150+ 160)/10 = 124

<u>MAD</u>

  • (24+14*3+4*3+16*3+16+26+36)/10 = 20.4

As we see the means are too different (75 vs 124) than MADs (15 vs 20.4).

7 0
3 years ago
Read 2 more answers
Whatbis the missing numerator of [2]5/6=?/6
Eva8 [605]

Answer:

10

Step-by-step explanation:

2* 5/6 = x/6

10/6 = x/6

Since the denominators are the same, the numerators are the same

x=10

5 0
3 years ago
Please answer this in two minutes
BartSMP [9]

Answer: 43.25?

Step-by-step explanation:

6 0
3 years ago
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