All categories

3 years ago

In 36 years, Ishaan will be 3 times as old as he is right now. How old is he right now?

Mathematics

2 answers:

DochEvi [55]3 years ago

4 0

Let Ishaan be x years
x + 36 = 3 x
36 = 2 x
x = 18
Ishaan is 18

Lady_Fox [76]3 years ago

3 0

Answer: He is 18 years old right now.

Step-by-step explanation:

Let the present age of Ishaan be x

After 36 years,

his age will be x+36

According to question,

it is mentioned that Ishaan will be 3 times as old as he is right now ,

So, we will frame it in equation:

$x+36=3x\\\\36=3x-x\\\\36=2x\\\\x=\frac{36}{2}\\\\x=18\ years$

Hence, he is 18 years old right now.

You might be interested in

Simplify this expression

I am Lyosha [343]

Hello there!

Let's put these into simpler terms:
-7s + 3s + 2s
10 - 8 - 7

-7s + 3s = -4s
-4s + 2s = 2s

10 - 8 = 2
2 - 7 = -5

We are now left with:
2s - 5, which is your simplified expression.

I hope this helps!

8 0

3 years ago

Perpendicular to y = 2x – 6<br> and passing through (4,3)

ladessa [460]

Answer:

y = - 1/2x + 5

Step-by-step explanation:

y = 2x – 6 slope = 2

Perpendicular line slope = -1/2

for (4 , 3) y = mx + b y = 3, x = 4, m = -1/2

b = y - mx = 3 - (-1/2) x 4 = 5

equation: y = - 1/2x + 5

5 0

3 years ago

What is the solution set to the inequality 7z+5>47

Vsevolod [243]

Answer:

$z>6$

<h2>Step-by-step explanation:</h2>

7z+5>47

Remove the 5:

$7z+5-5>47-5\\7z>42$

Divide by 7 to get z by itself:

$\frac{7z}{7} >\frac{42}{7} \\z>6$

5 0

3 years ago

Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx

uranmaximum [27]

Given the differential equation

$5t^3 \frac{dx}{dt} +2x-2=0$

The solution is as follows:

$5t^3 \frac{dx}{dt} +2x-2=0 \\ \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\ \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\ \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\ \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\ \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\ \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\ \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\ \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1$

3 0

3 years ago

At the city museum, child admission is $5.80 and adult admission is $9.60. On Friday, three times as many adult tickets as child

noname [10]

Its 74 and if its wrong im sorry but hi

7 0

3 years ago