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Art [367]
3 years ago
10

Which function passes through the points (2, 15) and (3, 26)?

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
7 0
<span>Which function passes through the points (2, 15) and (3, 26)?
</span> 
Its B
Basile [38]3 years ago
7 0

Answer:  The correct option is (B) y=11x-7.

Step-by-step explanation:  We are given to select the function that passes through the points (2, 15) and (3, 26).

Since the function passes through two points, so it must be a linear function in two variables.

That is, the graph of the function will be a straight line.

Now,

the slope of the line passing through the points (2, 15) and (3, 26) is given by

m=\dfrac{26-15}{3-2}\\\\\\\Rightarrow m=11.

Since the line passes through the point (2, 15), so the equation of the line will be

y-15=m(x-2)\\\\\Rightarrow y-15=11(x-2)\\\\\Rightarrow y-15=11x-22\\\\\Rightarrow y=11x-22+15\\\\\Rightarrow y=11x-7.

Thus, the required function is y=11x-7.

Option (B) is correct.

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Adam is hired at a salary of $50000 per year but will earn an annual increase of 2.5% per year. Brock is hired at the same time
nadezda [96]
A=50000(1.025^t), B=50000+3000t

A(10)=$64004.23, B(10)=$80000

So Brock will be earning $15995.77 more than Adam in the tenth year.
4 0
3 years ago
The table shows sets of ordered pairs that form a relation.
tiny-mole [99]

A relation is a relationship between sets of values. In math, the relation is between the x-values and y-values of ordered pairs. The set of all x-values is called the domain of the relation, and the set of all y-values is called the range of the relation.

A relation from a set X (domain) to a set Y (range) is called a function if each element of X is related to exactly one element in Y.

A. A relation {(2,-3), (3,-3), (1,4), (9,2)} is a function, because each x has exactly one element y related to.

B. A relation {(8,-3), (3,8), (9,4), (-2,2)} is a function,  because each x has exactly one element y related to.

C. A relation {(1,-1), (4,8), (9,-1), (3,2)}  is a function,  because each x has exactly one element y related to.

D. A relation {(1,-1), (-1,5), (1,-6), (-3,2)} is not a function, because x=1 has two possible outcomes y: y=-1 or y=-6.

Answer: A, B and C are functions and D is not a function

4 0
3 years ago
a 3 pound tub of butter at n dollars per pound costs $3.85. select the equation that most accurately depicts the word problem
Oksi-84 [34.3K]
<span>the equation that most accurately depicts the word problem  is
3xn=$3.85
proof
n=</span>
<span>n=$3.85/3=$1.28
the price is $1.28 per pound, 3 pound costs 3x$1.28=$3.85
</span>
4 0
3 years ago
Read 2 more answers
Need help with this question. Thank you!
Paul [167]

Answer:

61.2

Step-by-step explanation:

Distribute the figure into three shapes. Triangle, and two rectangles.

Find the area.

8 0
3 years ago
Read 2 more answers
A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a
Rashid [163]

Answer:

Length of original rectangle: 11 units.

\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}

\text{Perimeter of new rectangle}=20

Step-by-step explanation:

Let x represent width of the original rectangle.  

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be x+6.

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be x-2.

The length of new rectangle would be x+6-4=x+2.

The area of new rectangle would be (x+2)(x-2).

Now we will equate area of new rectangle with 21 and solve for x as:

(x+2)(x-2)=21

Applying difference of squares, we will get:

x^2-2^2=21

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x^2-4+4=21+4

x^2=25

Since width cannot be negative, so we will take positive square root of both sides.

\sqrt{x^2}=\sqrt{25}

x=5

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Length of the original rectangle would be x+6\Rightarrow x+5=11.

Therefore, the length of original rectangle is 11 units.

\text{Area of original rectangle}=5\times 11

\text{Area of original rectangle}=55    

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}

We know that perimeter of rectangle is two times the sum of length and width.

\text{Perimeter of new rectangle}=2((x+2)+(x-2))

\text{Perimeter of new rectangle}=2((5+2)+(5-2))

\text{Perimeter of new rectangle}=2(7+3)

\text{Perimeter of new rectangle}=2(10)

\text{Perimeter of new rectangle}=20

Therefore, the perimeter of the new rectangle is 20 units.

7 0
3 years ago
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