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horsena [70]
3 years ago
5

ASAP What statements are true regarding the given statement and diagram?

Mathematics
2 answers:
Kazeer [188]3 years ago
5 0

Answer:

1st option is right ok I have given you the correct answer

Olin [163]3 years ago
3 0
All of them are correct except the third and last statements
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What is the measure of QS?
riadik2000 [5.3K]

Answer:

21.9mm

Step-by-step explanation:

6.2+ 15.7 = 21.9

hope this helps....

3 0
3 years ago
Read 2 more answers
-37=5w-7 <br><br> w=<br><br><br> Please I need an answer ASP
grin007 [14]

Answer:

-6

Step-by-step explanation:

-37+7=5w

-30=5w

w=-30÷5

w=-6

5 0
3 years ago
Read 2 more answers
Can you please solve this I don't understand perpendicular lines
stira [4]

Answer:

The equation of the perpendicular line 't' is  3x+y =0

Point slope form y = mx +C

                            y = - 3x

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equation  s = \frac{1}{3}x +10    and given point (1,-3)

The equation of the perpendicular line

                        y =\frac{x+30}{3}

                 ⇒  3 y = x+30

               ⇒ x - 3y +30 =0

<u><em>Step(ii):-</em></u>

<em>The perpendicular line of the given straight line 's'</em>

<em>        b x -ay +k=0</em>

⇒  -3x -y +k=0

This line is passing through the point (1,-3)

     -3(1)-(-3)+k=0

            k =0

The equation of the perpendicular line   -3x-y =0

<u><em>Final answer:-</em></u>

The equation of the perpendicular line   3x+y =0

Point slope form y = mx +C

                            y = - 3x

                           

7 0
3 years ago
A coin is tossed $9$ times, and at least $7$ of the tosses were heads. How many different sequences of tosses could there have b
melamori03 [73]

Answer:

  • <u>46</u>

Explanation:

<u>1. Number of sequences with exactly seven heads:</u>

  • First head can go in 9 different positions
  • Second head can go in 8 different positions
  • Third head can go in 7 different positions
  • Fourth head can go in 6 different positions
  • Fifth head can go in 5 different positions
  • Sixth head can go in 4 different positions
  • Seventh head can go in 3 different positions

That gives: 9×8×7×6×5×4×3

Since all the heads are equivalent, you have repetitions that are not different. Then, you must discount the combinations that are equivalent.

In how many ways seven heads can be arranged? 7×6×5×4×3×2×1

Then, you must divide 9×8×7×6×5×4×3 by 7×6×5×4×3×2×1.

  • That is: 9 × 8 / 2 = 36 different ways of tossing seven heads

<u>2. Number of sequences with exactly eight heads:</u>

Following the same reasoning:

  • 9×8×7×6×5×4×3×2 divided by 8×7×6×5×4×3×2×1 = 9

  • That is 9 different ways of tossing eight heads.

<u>3. Number of sequences with exactly nine heads</u>

That is only one way: when all the tosses are heads: 1

<u>4. Number of sequences with at least seven heads</u>

Add the combinations of having exactly seven heads, eight heads and nine heads:

  • 36 + 9 + 1 = 46 ← answer
5 0
3 years ago
Can someone plz solve for A&amp;B? Plz and if you do thank you so much :)
Anna71 [15]

Answer:

Part a-

area= 35

perimeter= 31

part b-

area= 25

perimeter= 18

Step-by-step explanation:

to find the area of a triangle you multiply 1/2Bh

so for part A:

A= \frac{1}{2} (10)(7) (honestly, you can just input the whole equation into the calculator)

A=(5)(7)

A= 35

and for part B:

A= \frac{1}{2}(8.34)(6)

A= (4.17)(6)

A=25.02 (or just 25)

THEN, to find the perimeter you add up all of the sides

so for part A:

P= 14 + 10 + 7 = 31

and for part B:

P= 4 \frac{1}{3} + 8 \frac{1}{3}  + 5 \frac{1}{3} = 17 \frac{3}{3} or 18

I hope this helps :)

3 0
3 years ago
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