Answer:
40x-24
3b(6c-3a+c)
Step-by-step explanation:
For the first one use distributive property and multiply each term by 8.
For the second one find a common factor which is 3b and divide all terms by that number.
The attached image represents the triangle after it has been enlarged
<h3>How to enlarge the triangle?</h3>
The given parameters are:
- Scale factor, k = -1/3
- Center, (a,b) = (-1,2)
From the graph, the coordinates of the triangle are:
A = (-4,2)
B = (-4,-4)
C = (-1,-4)
The rule of dilation is calculated using:

So, we have:

A' = (0, 2)

B' = (0, 4)

C' = (-1, 4)
See attachment for the image of the triangle, after it has been enlarged
Read more about dilation at:
brainly.com/question/3457976
#SPJ1
Part A.
Using the Pythagorean theorem,
PR² = PQ² +QR²
PR² = (14 ft)² +(6 ft)² = 196 ft² +36 ft² . . . . substitute the given numbers
PR² = 232 ft² . . . . . . . . . . . . . . . . . . . . . . . .find the sum
PR = √(232 ft²) ≈ 15.23 ft . . . . . . . . . . . . . take the square root
The length of rod PR is 15.23 ft.
Part B.
Using the Pythagorean theorem,
PR² = PQ² +QR²
(16 ft)² = (14 ft)² +QR² . . . . . . . substitute the given numbers
256 ft² -196 ft² = QR² . . . . . .. subtract 14²
60 ft² = QR² . . . . . . . . . . . . . . find the sum
√(60 ft²) = QR ≈ 7.75 ft . . . . . take the square root
The new height QR is about 7.75 ft.
For this case we have the following polynomial:

The first thing to do is to place the variables on the same side of the equation.
We have then:

We complete the square by adding the term (b / 2) ^ 2 on both sides of the equation.
We have then:

Rewriting we have:

Therefore, the solutions are:
Answer:
the solution set of the equation is: