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Trava [24]
2 years ago
10

A 50.5 L flask contains 3.25 mol of an unknown gas at 288.6 K, what is the pressure of this gas?

Chemistry
1 answer:
Ivahew [28]2 years ago
3 0

Answer:

1.52atm is the pressure of the gas

Explanation:

To solve this question we must use the general gas law:

PV = nRT

<em>Where P is pressure in atm = Our incognite</em>

<em>V is volume = 50.5L</em>

<em>n are moles of gas = 3.25moles</em>

<em>R is gas constat = 0.082atmL/molK</em>

<em>And T is absolute temperature = 288.6K</em>

To solve pressure:

P = nRT / V

P = 3.25mol*0.082atmL/molK*288.6K / 50.5L

P = 1.52atm is the pressure of the gas

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