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Mazyrski [523]
2 years ago
13

9) Give the set of four quantum numbers that could represent the extra electron added (using the Aufbau principle) to the neutra

l Ne atom.
10) Which 2nd period element has the most negative electron affinity? Why? Bonus questions
11) Which ionization process requires the most energy? Why?
A) Se(g) → Set(g) + e-
B) Set(g) Se2+(g) +
C) Br(g) → Brt(g) + e-
D) Brt(g) Br2+(g) + e-
12) Place the following in order of decreasing metallic character. Explain your reason.
P As K
Chemistry
1 answer:
Pie2 years ago
3 0

Answer:

See explanation

Explanation:

9) If an extra electron is added to the neon atom, then the electronic configuration becomes; 1s2 2s2 2p6 3s1

This last electron has quantum numbers;

n=3, l=0, m=0 and s = +1/2

This is so because the 2s level is already filled so the extra electron must go into the 3s level. The orbital quantum number and the magnetic quantum number for the s orbital is zero.

10) Electron affinity is the energy released when one mole of gaseous atoms accept one mole of gaseous electrons to form one mole of gaseous ions having a negative charge.

In the second period, fluorine has the greatest electron affinity since electron affinity increases across the period. The noble gas, neon has an electron affinity of 0KJ/mol.

11) Ionization energy decreases down the group but increases across the period due to increase in the size of the nuclear charge and decrease in the distance between the nucleus and the outermost electron. Hence, the process; Br+(g) ---->Br2+(g) + e- has the greatest ionization energy. Recall that the second ionization is always higher than the first ionization energy.

12)The order of decreasing metallic character here is K> As> P. Even though As and P belong to the same group, we must note that metallic character increases down the group hence the order written above.

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lana66690 [7]

Answer:

2Fe2 S3+6O2 → 2Fe2O3+3SO2

Explanation:

4 0
2 years ago
Your friend the archaeologist, who studies the ancient human past, has asked you to find a numerical date for some hominid artif
natulia [17]

Answer:

I think it the carbon 14 which is a half life of 5730 because in 4.5billion years ago I don't think any human being existed on earth I'm not sure I hope that I helped you and good luck .

3 0
2 years ago
How many are molecules ( or formula) in each sample?
andre [41]

Answer:

  • 4.010 \times 10^{25} \text { molecules of } \mathrm{NaHCO}_{3} \text { present in } 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}
  • 16.86 \times 10^{26} \text { molecules of } \mathrm{Na}_{3} \mathrm{PO}_{4} \text { present in } 459 \mathrm{kg}\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}

<u>Explanation</u>:

<u>Number of molecules for 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}</u>

\text { Firstly molar mass is calculated of } \mathrm{NaHCO}_{3}:

Atomic mass of Na + H + C + 3(O)  = 22.99 + 1.008 + 12.01 + 3 × 16.00 = 84.00 g/mol

\text { Number of molecules of } \mathrm{NaHCO}_{3} \text { in } 55.93 \text { kg are as follows: }

55.93 \times\left(10^{3} \mathrm{gm}\right) \times \frac{1 \mathrm{mol} \mathrm{NaHCO}_{3}}{84.00 \mathrm{gm} \mathrm{NaHCO}_{3}} \times\left(6.022 \times 10^{23} \mathrm{molecules} \text { i.e Avogadro number }\right)

=4.010 \times 10^{26} \text { molecules of } \mathrm{NaHCO}_{3} \text { present in } 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}

<u>Number of molecules for for \left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}</u>

\text { Firstly molar mass is calculated of } \mathrm{Na}_{3} \mathrm{PO}_{4}

= Atomic mass of 3(Na) + P + 4(O)

= 3(22.99) + 30.97 + 4(16.00) = 163.94 g/mol

459 \times\left(10^{3} \mathrm{gm}\right) \times \frac{1 \mathrm{mol} N a_{3} P O_{4}}{163.94 \mathrm{gm} N a_{3} P O_{4}} \times\left(6.022 \times 10^{23} \mathrm{molecules} \text { i.e Avogadro number) } / 1 \mathrm{mol}\right.

=16.86 \times 10^{26} \text { molecules of } \mathrm{Na}_{3} \mathrm{PO}_{4} \text { present in } 459 \mathrm{kg}\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}

8 0
3 years ago
NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!
Paraphin [41]
<h2>Answer:  C) 1s²2s²2p⁶</h2>

<h3>Explanation:</h3>

A noble gas has 8 electrons between the p and s orbitals of the outer shell. Helium is the exception because it only has two electrons.

<h3>                       ∴  1s²2s²2p⁶ is the noble gas (neon)</h3>

7 0
2 years ago
Please explain how roasting a hot dog over a fire involves all three forms of heat transfer. Please use full sentences and corre
sergejj [24]

Ok so First of all we start with the fire. The fire gives off radiation because you can feel the heat through space. The fire also gives of conduction because you put the hotdog on the fire to cook it, and the hotdog will give off steam when it is hot causing it to give of Convection.

There is how cooking a hotdog over a fire uses all three heat transfer

3 0
3 years ago
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