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2 years ago

9

If $1000 is invested at 8% interest, compounded annually, then after n years the investment is worthan = 1000(1.08)ndollars.(a)

Find the first five terms of the sequence {an}. (Round your answers to the nearest cent.)a1 = $a2 = $a3 = $a4 = $a5 = $(b) Is the sequence convergent or divergent?

1 answer:

Luba_88 [7]2 years ago

5 0

Answer:

Diverge

Step-by-step explanation:

(a)

1st year: $1000 * 1.08^1 = \$1080$

2nd year: $1000 * 1.08^2 = \$1166.4$

3rd year: $1000 * 1.08^3 = \$1259.71$

4th year: $1000 * 1.08^4 = \$1360.49$

5th year: $1000 * 1.08^5 = \$1469.33$

(b) The sequence is divergent, because if we take the derivative of the function with respect to n year:

$(1000*1.08^n)^{'} = 1000ln(n)*1.08^n$

This is a positive, meaning the slope of the function is positive. If we take the second derivative using product rule

$(1000ln(n)*1.08^n)^{'} = 1000\frac{ln(n)}{n}1.08^n$

This is also positive when n > 0. Therefore, the slope is positive and increasing. This means the sequence diverges.

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What is the area of the shaded region?

kolezko [41]

Answer:

110 cm^2

Step-by-step explanation:

The first thing that you need to do is find the area of triangle AFE. The area of a triangle is always base*height/2. So in this case, that would be 10*6 divided by 2, which is 30 cm. Next, you will need to know the area of triangle ECB. Using that same formula, you will get 8*10/2, which is 40 cm. Finally, you will need to find the area of the whole rectangle. The area of a rectangle is always the length times the width. In this case, you would have 10*18, which is 180 cm. To get your final answer, you need to subtract the areas of the unshaded area from the whole area. That would be 180-(30+40), which is 110 cm. I hope this helped!

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1 year ago

Solve the inequality shown below.<br> -2(q-22)+q+12>0

Andru [333]

<span><span><span><span>−<span>2<span>(<span>q−22</span>)</span></span></span>+q</span>+12</span>>0</span>
Step 1: Simplify both sides of the inequality.<span><span><span>
−q</span>+56</span>>0</span>
Step 2: Subtract 56 from both sides.<span><span><span><span>
−q</span>+56</span>−56</span>><span>0−56</span></span><span><span>
−q</span>><span>−56</span></span>
Step 3: Divide both sides by -1.<span><span><span>
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Answer: q<56

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2 years ago

Below is the five-number summary for 144 hikers who recently completed the John Muir Trail (JMT). The variable is the amount of

bearhunter [10]

Answer:

The IQR is given by:

$IQR = Q_3 -Q_1 = 28-18= 10$

If we want to find any possible outliers we can use the following formulas for the limits:

$Lower= Q_1 - 1.5 IQR$

$Upper= Q_3 + 1.5 IQR$

And if we find the lower limt we got:

$Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3$

$Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43$

So then the left boundary for this case would be 3 days

Step-by-step explanation:

For this case we have the following 5 number summary from the data of 144 values:

Minimum: 9 days

Q1: 18 days

Median: 21 days

Q3: 28 days

Maximum: 56 days

The IQR is given by:

$IQR = Q_3 -Q_1 = 28-18= 10$

If we want to find any possible outliers we can use the following formulas for the limits:

$Lower= Q_1 - 1.5 IQR$

$Upper= Q_3 + 1.5 IQR$

And if we find the lower limt we got:

$Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3$

$Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43$

So then the left boundary for this case would be 3 days

6 0

2 years ago

Does anybody know how to do time with exponential decay

My name is Ann [436]

<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

$b_n=0.12\times b_{n-1}$

Why does this work? Initially, you start with 500 mL of air that you breathe in, so $b_1=500\text{ mL}$ . After the second breath, you have 12% of the original air left in your lungs, or $b_2=0.12\timesb_1=0.12\times500=60\text{ mL}$ . After the third breath, you have $b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}$ , and so on.

You can find the amount of original air left in your lungs after $n$ breaths by solving for $b_n$ explicitly. This isn't too hard:

$b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots$

and so on. The pattern is such that you arrive at

$b_n=0.12^{n-1}b_1$

and so the amount of air remaining after $50$ breaths is

$b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}$

which is a very small number close to zero.</span>

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2 years ago

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enyata [817]

Answer:

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Step-by-step explanation:

So a unit rate is measuring how much of something is there if one unit of another thing is present. In this case, there are 8 servings and 880 calories. Now, simply divide both sides by 8 in order to get the unit rate for each serving:

880/8 ---> 110 calories per serving

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2 years ago