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Tom [10]
3 years ago
10

Can y’all please help me?!

Mathematics
1 answer:
Hatshy [7]3 years ago
4 0

Answer:

a and b are correct

Step-by-step explanation:

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Find the length of the function over the given interval. y = 3x from x = 0 to x = 2
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The length of the function y = 3x over the given interval [0, 2] is 3.2 units

For given question,

We have been given a function  y = 3x

We need to find the length of the function on the interval x = 0 to x = 2.

Let f(x) = 3x where f(x) = y

We have  f'(x) = 3,  so  [f'(x)]² = 9.  

Then the arc length is given by,

\int\limits^a_b {\sqrt{1+[f'(x)]^2} } \, dx\\\\= \int\limits^2_0 {\sqrt{1+9} }\, dx\\\\=\sqrt{10}\\\\ =3.2

This means, the arc length is 3.2 units.

Therefore, the length of the function y = 3x over the given interval [0, 2] is 3.2 units

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2 years ago
The admissions officer for Clearwater College developed the following estimated regression equation relating the final college G
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A. Complete the missing entries in this Excel Regression tool output. Enter negative values as negative numbers. ANOVA df SS MS F Significance F Regression 2 .8811 52.4464 Residual 7 .1179 .0168 Total Coefficients Standard Error t Stat P-value Intercept X1 X2.

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dlinn [17]
We are given two sides and their included angle. Using the side-angle-side method we can find the Area of the triangle using the following formula:

Area = 0.5 ab sin(γ)

a = Measure of first side = 3.2 feet
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Using the values in the above formula, we get:

Area = 0.5 x ( 3.2) x (4.7) x (sin(62))

Area = 6.64 square feet (rounded to nearest hundredth) 

Thus, the Area of the given triangle is 6.64 square feet
7 0
3 years ago
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