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ExtremeBDS [4]
2 years ago
15

Solve for x. round to the nearest tenth. If necessary​

Mathematics
1 answer:
Step2247 [10]2 years ago
7 0
1.9

Do sin54 * 2.3
Because sin54 = x/2.3
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Vinvika [58]
(X,Y)

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6 0
3 years ago
Somebody’s please help me with this it’s due tomorrow and I don’t have any idea how to do it
svet-max [94.6K]

Answer:

1) They will stop 10 times for a break

2) A baker can make 10 cakes

3) Tammy will distrubute 36 bags with 2 1/2 pounds of candy

Step-by-step explanation:

Let me know if you have any questions !

Hope it helps

3 0
2 years ago
Natalie added 20 pieces of candy to a bowl. Two days later, half of the candy in the bowl is gone. If there are 14 pieces left i
Salsk061 [2.6K]

Answer:

8 pieces of candy

Step-by-step explanation:

Take the original amount of candy in the bowl to be x.

It says that 20 pieces of candy were added, therefore there are x+20 pieces of candy in the bowl.

Half of the candy is gone, therefore \frac{x+20}{2} pieces of candy are left in the bowl.

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8 0
3 years ago
More on Areas. Farmer Jones, and his wife, Dr. Jones, both mathematicians, decide to build a fence in their field to keep the sh
Olin [163]

Answer:

Area covered by the fences will be 16.1 unit²

Step-by-step explanation:

Let the first parabola is represented by the function f(x) = 6x²

and second parabola by g(x) = x² + 9

point of intersection of the graphs will be determined when f(x) = g(x)

6x² = x² + 9

5x² = 9

x² = 1.8

x = ± 1.34

Now we will find the area between these curves drawn on the graph.

Area = \int_{-1.34}^{1.34}[f(x)-g(x)]dx=\int_{-1.34}^{1.34}[6x^{2}-(x^{2}+9)]dx

= \int_{-1.34}^{1.34}(5x^{2}-9)dx

= [\frac{5}{3}x^{3}-9x]_{-1.34}^{1.34}

= [\frac{5}{3}(-1.34)^{3}-9(-1.34)-\frac{5}{3}(1.34)^{3}+9(1.34)]

= [-4.01+12.06-4.01+12.06]

= 16.1 unit²

6 0
3 years ago
3 2/6 + ( 2 1/6 + 4/6 )
stellarik [79]

Answer:

5 7/6 or 6 1/6 either one works they are the same number just one is not simplified

3 0
3 years ago
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