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4 years ago

11

4x-3=2x+7 HELP PLEASEEE

2 answers:

Mkey [24]4 years ago

6 0

Answer:

x = 5

Step-by-step explanation:

Given

4x - 3 = 2x + 7 ( subtract 2x from both sides )

2x - 3 = 7 ( add 3 to both sides )

2x = 10 ( divide both sides by 2 )

x = 5

grigory [225]4 years ago

3 0

Answer:

x=5

Step-by-step explanation:

you will start by subtracting 2x from 4x then you are left with 2x-3=7. then you will add 3 to 7 that will give you 2x=10, then divide 2 from 10. from there you get x=5.

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Which expression represents the algebraic phrase “eleven less than seven times a number”?

Rzqust [24]

The answer would be 7x - 11.

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4 years ago

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The graph below represents the amount of change Jaxon would receive, y, if he bought a item with a cost of x. Which equation rep

harina [27]

Answer:

1. y = 10 - x

Step-by-step explanation:

Because he starts off with 10 dollars, and x is the amount he spends on an item, y is showing the change that he would get from paying with a 10 dollar bill, so it's what's left over from that 10 dollars.

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3 years ago

In a standard (x,y) coordinate plane, point M is located at (-4 1/2, 18 1/3) and N is located at (-4 1/2, -2 2/3.) Find the leng

Harrizon [31]

Answer:

$\frac{ - 9}{2} + \frac{9}{2} = 0$

$\frac{55}{3} + \frac{8}{3} = \frac{63}{3}$

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4 0

3 years ago

Find the square root. <br> -√1/9

harina [27]

Answer:

-1/9

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3 years ago

Carbon-14 is a radioactive isotope that has a half-life of 5,730 years. Approximately how many years will it take for carbon-14

PilotLPTM [1.2K]

Answer:

<em>Carbon-14 will take 19,035 years to decay to 10 percent.</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay.

An exponential decay can be described by the following formula:

$N(t)=N_{0}e^{-\lambda t}$

Where:

No = The quantity of the substance that will decay.

N(t) = The quantity that still remains and has not yet decayed after a time t

$\lambda$ = The decay constant.

One important parameter related to radioactive decay is the half-life:

$\displaystyle t_{1/2}=\frac {\ln(2)}{\lambda }$

If we know the value of the half-life, we can calculate the decay constant:

$\displaystyle \lambda=\frac {\ln(2)}{ t_{1/2}}$

Carbon-14 has a half-life of 5,730 years, thus:

$\displaystyle \lambda=\frac {\ln(2)}{ 5,730}$

$\lambda=0.00012097$

The equation of the remaining quantity of Carbon-14 is:

$N(t)=N_{0}e^{-0.00012097\cdot t}$

We need to calculate the time required for the original amout to reach 10%, thus N(t)=0.10No

$0.10N_o=N_{0}e^{-0.00012097\cdot t}$

Simplifying:

$0.10=e^{-0.00012097\cdot t}$

Taking logarithms:

$ln 0.10=-0.00012097\cdot t$

Solving for t:

$\displaystyle t=\frac{log 0.10}{-0.00012097}$

$t\approx 19,035\ years$

Carbon-14 will take 19,035 years to decay to 10 percent.

6 0

3 years ago

Read 2 more answers