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cricket20 [7]
3 years ago
6

Choose the quadratic equation that has a leading coefficient of 1 and solutions 3 and -2.

Mathematics
1 answer:
ss7ja [257]3 years ago
6 0

Answer:

Option D x^{2} -x-6=0

Step-by-step explanation:

Verify each quadratic equation

case A) we have

x^{2} +x+6=0

This quadratic equation has a leading coefficient of 1

Substitute the value of x=3 and x=-2 in the equation

For x=3

(3)^{2} +(3)+6=0

18=0 ----> is not true

therefore

x=3 is not a solution of the quadratic equation

case B) we have

x^{2} -x-5=0

This quadratic equation has a leading coefficient of 1

Substitute the value of x=3 and x=-2 in the equation

For x=3

(3)^{2} -(3)-5=0

1=0 ----> is not true

therefore

x=3 is not a solution of the quadratic equation

case C) we have

x^{2} +x+5=0

This quadratic equation has a leading coefficient of 1

Substitute the value of x=3 and x=-2 in the equation

For x=3

(3)^{2} +(3)+5=0

17=0 ----> is not true

therefore

x=3 is not a solution of the quadratic equation

case D) we have

x^{2} -x-6=0

This quadratic equation has a leading coefficient of 1

Substitute the value of x=3 and x=-2 in the equation

For x=3

(3)^{2} -(3)-6=0

0=0 ----> is true

therefore

x=3 is a solution of the quadratic equation

For x=-2

(-2)^{2} -(-2)-6=0

4+2-6=0

0=0 ----> is true

therefore

x=-2 is a solution of the quadratic equation

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