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nirvana33 [79]
3 years ago
7

Using {0,1,3,4,5,6,9}, how many four-digit numbers with different digits can be produced between 4000 to 5000, if the numbers mu

st be divisible by 9?
Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0

Answer:18

Step-by-step explanation:

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- - Use the Quadratic Formula to solve the equation x2 – 2x = -9.​
mina [271]

No solution


Hope that helps

4 0
2 years ago
Find the sum.<br> 46+(−3)
lord [1]

Answer:

43

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
According to a study done by Nick Wilson of Otago University Wellington, the probability a randomly selected individual will not
Lorico [155]

Answer and Step-by-step explanation:

From the question statement we get know that it is Binomial distribution because there are only two possible outcomes so we need to use Binomial Probability Distribution for this question.

Formula for the Binomial Probability Distribution:

P(X)=   p^x q^(n-x)

Where,

  • C_x^n=n!/(n-x)!x!   (i.e. combination)
  • x= total number of successes
  • p=probability of success (p=1-q)  
  • q=probability of failure (q=1-p)
  • n=number of trials
  • P(X)= probability of total number of successes

Answer and explanation for each part of the question are as follow:

a.What is the probability that among 10 randomly observed individuals exactly 4 do not cover their mouth when sneezing?

Solution:

Given that

n=10  

p=0.267 (because p is the probability of success which is “number of individuals not covering their mouths when sneezing” in the question)

q=1-0.267=0.733  

x=4 (number of successes i.e. individuals not covering their mouths)

C_x^n=n!/(n-x)!x!=10!/(10-4)!4!=210

P(X)=C_x^n   p^x q^(n-x)=210×〖(0.267)〗^4×〖0.733〗^(10-4)

P(X)=210×0.00508×0.155  

P(X)=0.165465  

b. What is the probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth when sneezing?

Solution:

Given that

n=10  

p=0.267 (because p is the probability of success which is “number of individuals not covering their mouths when sneezing” in the question)

q=1-0.267=0.733  

x=3 (number of successes i.e. individuals not covering their mouths)

C_x^n=n!/(n-x)!x!=10!/(10-3)!3!=120

P(X)=C_x^n   p^x q^(n-x)=120×(0.267)^3×〖0.733〗^(10-3)

P(X)=120×0.01903×0.1136  

P(X)=0.25962  

c. Would you be surprised if, after observing 18 individuals, fewer than half covered their mouth when sneezing? why?

Solution:

Given that

n=18  

p=0.267 (because p is the probability of success which is “number of individuals not covering their mouths when sneezing” in the question)

q=1-0.267=0.733  

x=9 (x is the number of successes “number of individuals not covering their mouths when sneezing”, if less than half cover their mouth then more than half will not cover), so let x=9

C_x^n=n!/(n-x)!x!=18!/(18-9)!9!=48620

P(X)=48620×(0.267)^9×〖0.733〗^(18-9)  

P(X)=48620×0.00000689×0.0610  

P(X)=0.020  

Yes, I am surprised that probability of less than 9 individuals covering their mouth when sneezing is 0.020. Which is extremely is small.

3 0
3 years ago
An airplane flies 3800 km in 4 hours 45 minutes. What is its average speed in kilometers per hour?
8_murik_8 [283]

Average speed = (distance covered in some time)  /  (time to cover the distance)

4 hours 45 minutes = 4-3/4 hours = 4.75 hours

Average speed  =  (3,800 km) / (4.75 hours)  =  800 km/hr
3 0
3 years ago
Read 2 more answers
Select all of the scales that are equivalent to 3 cm to 4 km.
ra1l [238]

In mathematics, a scale can be described in charts as a marking system at predefined times, which determines the relationship between the units that are being used and their images on the graph, and the further calculation can be defined as follows:

  • Since in this question, the ratio is between 3 cm to 4 km you can make a \bold{\frac{3}{4}=\frac{cm}{km}} split, and if you are split between 3 and 4, you get the ratio between \bold{\frac{\frac{3}{4 \ cm}}{1\ km} = \frac{3\ cm}{ 4\ km}}.

         \bold{\to \frac{3 }{ 4}= 0.75}

Therefore the final answer is "0.75 cm to 1 km"

Learn more:

brainly.com/question/15285394

6 0
2 years ago
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