Let f_n be the number of rabbit pairs at the beginning of each month. We start with one pair, that is f_1 = 1. After one month the rabbits still do not produce a new pair, which means f_2 = 1. After two months a new born pair appears, that is f_3 = 2, and so on. Let now n $\geq$ 3 be any natural number. We have that f_n is equal to the previous amount of pairs f_n-1 plus the amount of new born pairs. The last amount is f_n-2, since any two month younger pair produced its first baby pair. Finally we have

f_1 = f_2 = 1,f_n = f_n-1 + f_n-2 for any natural n $\geq$ 3.

5 0

3 years ago

How do you find the answer to 8/10 divided by 1/5

kherson [118]

When fractions are divided by each other, you're really multiplying by the "multiplicative inverse". This is the fraction, but flipped.

$\frac{8}{10} \div \frac{1}{5} = \frac{8}{10} \times \frac{5}{1} \\\\So\\\frac{8}{10} \times \frac{5}{1} = \frac{40}{10} = 4$

8 0

4 years ago

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