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3 years ago

I need help... I honestly don’t know.

Mathematics

2 answers:

Serhud [2]3 years ago

8 0

Answer:

∡ABC=55°

Step-by-step explanation:

Step 1: Identify all angles

∠A=(x+45)°

∠B=(6x+5)°

∠C=(3x)°

∠ABC=(180-∠B)°=(180-(6x+5))°

Step 2: Use the Triangle Angle Sum Theorem

∠A+∠ABC+∠C=180°

(x+45)+(180-(6x+5))+(3x)=180

x+45+180-6x-5+3x=180

-2x+45+180-5=180

-2x+45-5=0

-2x+40=0

-2x=-40

x=20

Step 3: Plug in x=20 for ∠ABC

∠ABC=(180-(6x+5))°

(180-6(20)-5)°

(180-120-5)°

(60-5)°

55°

So ∡ABC=55°

stepan [7]3 years ago

4 0

Answer:

∡ABC=55°

Step-by-step explanation:

Step 1: Identify all angles

∠A=(x+45)°

∠B=(6x+5)°

∠C=(3x)°

∠ABC=(180-∠B)°=(180-(6x+5))°

Step 2: Use the Triangle Angle Sum Theorem

∠A+∠ABC+∠C=180°

(x+45)+(180-(6x+5))+(3x)=180

x+45+180-6x-5+3x=180

-2x+45+180-5=180

-2x+45-5=0

-2x+40=0

-2x=-40

x=20

Step 3: Plug in x=20 for ∠ABC

∠ABC=(180-(6x+5))°

(180-6(20)-5)°

(180-120-5)°

(60-5)°

55°

So ∡ABC=55°

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