It would be: 0.25 = 25/100 = 1/4
so, your answer is 1/4
Answer:
6a) i- 2hrs 36mins ii- 3hrs 12mins
b) car A≈ 76.9km/h car B≈ 62.5km/h
c)------
7a) 35km
b) car A=75km car B=60km
c) 30km
d) car A≈36mins car B≈48mins
Step-by-step explanation:
6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.
b) Using the answer from a, you divide 200km by the time.
For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6
∴ car A: 200/2.6≈ 76.92km/h
For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2
∴ car B: 200/3.2≈ 62.5km/h
7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.
b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).
c) Difference from car A line to car B:
155km-125km=30km
d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.
Hope this helps.
Answer:
w = 20
Step-by-step explanation:
We need to solve the equation, to find the value of w:
w - 8 = 12 - we need to add 8 to both sides
w - 8 + 8 = 12 + 8 - the -8 and the +8 on the left hand side cancel out to give just w
w = 20
Step-by-step explanation:
The vertical angles are congruent. The right angles are congruent. There are 2 angles of a triangle congruent to 2 angles of anther triangle. By AA Similarity the triangles are similar.
Statement A. (vertical angles are congruent)
Statement D. (right angles are congruent)
Triangle AEC is similar to triangle BDC.
Statement E is true but does not help.
Correct statement of proportional side lengths:
BD/AE = CD/CE
x/150 = 200/50
x/150 = 4
x = 600
P.S. I think there is a mistake in the problem. I don't think that statement E is correct. It is a true statement, but it is useless. Statement F is false.
