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KIM [24]
3 years ago
6

Please someone help me I'm stuck on my homework for at least a hour

Mathematics
1 answer:
miss Akunina [59]3 years ago
6 0

Pi is 3.14

1st # is 3.13

2nd # is 3.15

These numbers are irrational because pi=infinity

( I am not exactly sure if this is right so don't blame me if you get this wrong, I just tried to help.....) :T

You might be interested in
Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 4 in the manner described. (Ent
QveST [7]

Answer:

x=2\cos(t) and y=-2\sin(t)+1

Step-by-step explanation:

(x-h)^2+(y-k)^2=r^2 has parametric equations:

(x-h)=r\cos(t) \text{ and } (y-k)=r\sin(t).

Let's solve these for x and y  respectively.

x-h=r\cos(t) can be solved for x by adding h on both sides:

x=r\cos(t)+h.

y-k=r \sin(t) can be solve for y by adding k on both sides:

y=r\sin(t)+k.

We can verify this works by plugging these back in for x and y respectively.

Let's do that:

(r\cos(t)+h-h)^2+(r\sin(t)+k-k)^2

(r\cos(t))^2+(r\sin(t))^2

r^2\cos^2(t)+r^2\sin^2(t)

r^2(\cos^2(t)+\sin^2(t))

r^2(1) By a Pythagorean Identity.

r^2 which is what we had on the right hand side.

We have confirmed our parametric equations are correct.

Now here your h=0 while your k=1 and r=2.

So we are going to play with these parametric equations:

x=2\cos(t) and y=2\sin(t)+1

We want to travel clockwise so we need to put -t and instead of t.

If we were going counterclockwise it would be just the t.

x=2\cos(-t) and y=2\sin(-t)+1

Now cosine is even function while sine is an odd function so you could simplify this and say:

x=2\cos(t) and y=-2\sin(t)+1.

We want to find \theta such that

2\cos(t-\theta_1)=2 \text{ while } -2\sin(t-\theta_2)+1=1 when t=0.

Let's start with the first equation:

2\cos(t-\theta_1)=2

Divide both sides by 2:

\cos(t-\theta_1)=1

We wanted to find \theta_1 for when t=0

\cos(-\theta_1)=1

Cosine is an even function:

\cos(\theta_1)=1

This happens when \theta_1=2n\pi where n is an integer.

Let's do the second equation:

-2\sin(t-\theta_2)+1=1

Subtract 2 on both sides:

-2\sin(t-\theta_2)=0

Divide both sides by -2:

\sin(t-\theta_2)=0

Recall we are trying to find what \theta_2 is when t=0:

\sin(0-\theta_2)=0

\sin(-\theta_2)=0

Recall sine is an odd function:

-\sin(\theta_2)=0

Divide both sides by -1:

\sin(\theta_2)=0

\theta_2=n\pi

So this means we don't have to shift the cosine parametric equation at all because we can choose n=0 which means \theta_1=2n\pi=2(0)\pi=0.

We also don't have to shift the sine parametric equation either since at n=0, we have \theta_2=n\pi=0(\pi)=0.

So let's see what our equations look like now:

x=2\cos(t) and y=-2\sin(t)+1

Let's verify these still work in our original equation:

x^2+(y-1)^2

(2\cos(t))^2+(-2\sin(t))^2

2^2\cos^2(t)+(-2)^2\sin^2(t)

4\cos^2(t)+4\sin^2(t)

4(\cos^2(t)+\sin^2(t))

4(1)

4

It still works.

Now let's see if we are being moving around the circle once around for values of t between 0 and 2\pi.

This first table will be the first half of the rotation.

t                  0                      pi/4                pi/2               3pi/4               pi  

x                  2                     sqrt(2)             0                  -sqrt(2)            -2

y                  1                    -sqrt(2)+1          -1                  -sqrt(2)+1            1

Ok this is the fist half of the rotation.  Are we moving clockwise from (2,1)?

If we are moving clockwise around a circle with radius 2 and center (0,1) starting at (2,1) our x's should be decreasing and our y's should be decreasing at the beginning we should see a 4th of a circle from the point (x,y)=(2,1) and the point (x,y)=(0,-1).

Now after that 4th, the x's will still decrease until we make half a rotation but the y's will increase as you can see from point (x,y)=(0,-1) to (x,y)=(-2,1).  We have now made half a rotation around the circle whose center is (0,1) and radius is 2.

Let's look at the other half of the circle:

t                pi               5pi/4                  3pi/2            7pi/4                     2pi

x               -2              -sqrt(2)                0                 sqrt(2)                      2

y                1                sqrt(2)+1             3                  sqrt(2)+1                   1

So now for the talk half going clockwise we should see the x's increase since we are moving right for them.  The y's increase after the half rotation but decrease after the 3/4th rotation.

We also stopped where we ended at the point (2,1).

3 0
3 years ago
A student finds the slope of the line between (8,7) and (1,4). She writes 17-4/1-8. What mistake did she make
Ksju [112]

Answer:

It's supposed to be 4-7/1-8

Step-by-step explanation:

The formula for slope is y1 - y2 / x1 - x2 (subscript). So you would take the y value from (8,7) which is 7, and subtract by the y value from (1,4), which is 4. You do the same for the x values and you get 7-4/8-1, which is 3/7.

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3 years ago
8. MAGAZINES You want to compare the number of words per sentence in a sports magazine to the number of words per sentence in a
igor_vitrenko [27]

Answer:

I also don't know so I am sorry I need point

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twenty-five percent of the cowboys who participated in the Texas cattle drives were African Americans. True False
Alla [95]

Answer:

False.

Step-by-step explanation:

Because they were slaves

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The senior class has 412 students. They are assigned to different homerooms. There are 28 students in the smallest homeroom and
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Subtract 28 from 412 and then divide that answer by 12
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