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kati45 [8]
3 years ago
8

What is your average speed if you walk 2 kilometers in 20minutes

Physics
2 answers:
goldenfox [79]3 years ago
3 0

Answer:

12 km/hr

Explanation:

Speed= Distance/Time

taurus [48]3 years ago
3 0

Answer:

12km/h

Explanation:

average speed= Distance covered /time taken

average speed=2km/20minutes

=but 1 minutes is 60 seconds

=2km/60minutes

=12km/h

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Over a span of 6.0 seconds, a car changes it's speed from 89 km/h to 37 km/h. What is its average acceleration in meters per sec
scoundrel [369]

Acceleration = (change in speed) / (time for the change)

change in speed = (speed at the end) - (speed at the beginning)

change in speed = (37 km/hr) - (89 km/hr) = -52 km/hr

Acceleration = (-52 km/hr) / (6 sec)

Acceleration = (-26/3) km/(hr·sec)

Units: (1/hr·sec) · (hr/3600 sec) = 1 / 3600 sec²

(-26/3) km/(hr·sec) = (-26/3) km/(3600 sec²)

= -26,000/(3 · 3600) m/s²

<em>Acceleration = -2.41 m/s²</em>

3 0
4 years ago
Suppose a rocket launches with an acceleration of 34.0 m/s2 what is the apparent weight of an 85-kg astronaut aboard this rocket
docker41 [41]

Answer:

the apparent weight of the astronaut in the rocket is 3723 N.

Given:

acceleration = 34 \frac{m}{s^{2} }

mass of astronaut = 85 kg

To find:

Apparent weight of the astronaut = ?

Solution:

Total weight of the astronaut in a rocket is given by,

W = w + F

W = apparent weight of the astronaut

w = weight of astronaut on earth surface = mg

F = force acting on the astronaut = ma

W = mg+ma

W = m (g+a)

W = 85 (9.8 + 34)

W = 3723 N

Thus, the apparent weight of the astronaut in the rocket is 3723 N.

7 0
3 years ago
Read 2 more answers
A truck heading east has an initial velocity of 6 m/s. It accelerates at 2 m/s2 for 12 seconds. What distance does the truck tra
omeli [17]
Vf = vi + at
vf = 6 + (2)(12)
vf = 6 + 24
vf = 30

2as = vf² - vi²
2(2)s = (30)² - (6)²
4s = 900 - 36
4s = 864
s = 864/4
s = 216
<span>d = 216</span>
6 0
3 years ago
Read 2 more answers
Two floors in a building are separated by 4.1 m. People move between the two floors on a set of stairs. (a) Determine the change
Ket [755]

Answer:

a) The change in potential energy of a 3.0 kilograms backpack carried up the stairs.

b) The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.

Explanation:

Let consider the bottom of the first floor in a building as the zero reference (z = 0\,m). The change in potential energy experimented by a particle (\Delta U_{g}), measured in joules, is:

\Delta U_{g} = m\cdot g\cdot (z_{f}-z_{o}) (1)

Where:

m - Mass, measured in kilograms.

g - Gravitational acceleration, measured in meters per square second.

z_{o}, z_{f} - Initial and final height with respect to zero reference, measured in meters.

Please notice that m\cdot g is the weight of the particle, measured in newtons.

a) If we know that m = 3\,kg, g = 9.807\,\frac{m}{s^{2}}, z_{o} = 0\,m and z_{f} = 4.1\,m, then the change in potential energy is:

\Delta U_{g} = (3\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.1\,m-0\,m)

\Delta U_{g} = 120.626\,J

The change in potential energy of a 3.0 kilograms backpack carried up the stairs.

b) If we know that m\cdot g = 650\,N, z_{o} = 4.1\,m and z_{f} = 0\,m, then the change in potential energy is:

\Delta U_{g} = (650\,N)\cdot (0\,m-4.1\,m)

\Delta U_{g} = -2665\,J

The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.

5 0
3 years ago
What is quantitative?
7nadin3 [17]
<span>To relate or measure the by the quantity of something, not against the quantity</span>
5 0
4 years ago
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