Answer:
E = 1/2 m v^2 = 1/2 k x^2 equating KE of coyote and spring
x^2 = m v^2 / k = 10 kg * 20^2 m^2 / s^2 / 400 N / m
x^2 = 10 * 400 / 400 (kg m^3 / kg-m) = 10 m^2
x = 3.16 m
There are some missing data in the problem. The full text is the following:
"<span>A </span>real<span> (</span>non-Carnot<span>) </span>heat engine<span>, </span>operating between heat reservoirs<span> at </span>temperatures<span> of 710 K and 270 K </span>performs 4.1 kJ<span> of </span>net work<span>, and </span>rejects<span> 9.7 </span>kJ<span> of </span>heat<span>, in a </span>single cycle<span>. The </span>thermal efficiency<span> of a </span>Carnot heat<span> engine, operating between the same </span>heat<span> reservoirs, in percent, is closest to.."
Solution:
The efficiency of a Carnot cycle working between cold temperature </span>

and hot temperature

is given by

and it represents the maximum efficiency that can be reached by a machine operating between these temperatures. If we use the temperatures of the problem,

and

, the efficiency is

Therefore, the correct answer is D) 62 %.
A displacement time graph is able to show if an object is going backwards or forwards for example usually a line with a negative gradient means going backwards (or back to the start) This CAN’T be shown on a distance time graph
A distance time graph shows how far an object has traveled in a given time
So for example...
Distance is plotted on the Y-axis
Time is plotted on the X-axis
So not they are not the same, hope this helped :)
Answer:
<h3>3.33m/s</h3>
Explanation:
Using the law of conservation of momentum
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are the velocities
v is the final velocity
Given
m1 = 50g
u1 = 10m/s
m2 = 100g
u2 = 0m/s (stationary ball)
Required
Common velocity v
Substitute
50(10) + 100(0) = (50+100)v
500 = 150v
v = 500/150
v = 3.33m/s
Hence the velocity of each ball immediately after the collision is 3.33m/s