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Brut [27]
3 years ago
11

Can someone help me answer this

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0
The answer is hopefully this helps!

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A classroom has a height of 8 feet and is 30 feet long. If the volume of the room is 6,000 ft 3 , how wide is the classroom?
Elza [17]
Height*length*width=volume, therefore 8*30*width=6000 therefore width=6000/240=25 feet
4 0
3 years ago
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What is 3/20 as a decimal equivalent
11Alexandr11 [23.1K]
3/20 as a decimal equivalent is <span>0.15</span>
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The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
Compute a value for t that satisfies the equation below. "-2/3" t - 2 = - 3
Dima020 [189]

Answer:

t = 3/2

Step-by-step explanation:

Instead of randomly guessing values of "t" that will satisfy the equation, you can easily find the correct value by solving the equation in terms of "t". In other words, you can set the equation equal to "t" to find the final answer.

(-2/3)t - 2 = -3                             <----- Original equation

(-2/3)t = -1                                   <----- Add 2 to both sides

t = 3/2                                        <----- Divide both sides by -2/3

You can check this value by plugging it into "t" and determining whether both sides of the equations will be equal.

(-2/3)t - 2 = -3                            <----- Original equation

(-2/3)(3/2) - 2 = -3                      <----- Plug 3/2 into "t"

-6/6 - 2 = -3                               <----- Multiply -2/3 and 3/2

-1 - 2 = -3                                    <----- Simplify -6/6

-3 = -3                                        <----- Subtract

6 0
2 years ago
how many x-intercepts will the graph of y=(x-2)^2 have?
tekilochka [14]

Answer:

1

Step-by-step explanation:

Because it y is 0 then we can find the X intercepts. so there will be one X intercept.

4 0
3 years ago
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