The formula is
A=p (1+r/k)^kt
A future value 3000
P present value 150
R interest rate 0.025
T time?
3000=150 (1+0.025/12)^12t
Solve for t
3000/150=(1+0.025/12)^12t
Take the log
Log (3000/150)=log (1+0.025/12)×12t
12t=Log (3000/150)÷log (1+0.025/12)
T=(log(3,000÷150)÷log(1+0.025÷12))÷12
T=119.95 years
the equation that we can solve using the given system of equations is:
3x^5 - 4x^4 - 11x^3 + 2x^2 - 10x + 15 = 0
<h3>Which equation can be solved using the given system of equations?</h3>
Here we have the system of equations:
y = 3x^5 - 5x^3 + 2x^2 - 10x + 4
y = 4x^4 + 6x^3 - 11
Notice that both x and y should represent the same thing in both equations, then we could write:
3x^5 - 5x^3 + 2x^2 - 10x + 4 = y = 4x^4 + 6x^3 - 11
If we remove the middle part, we get:
3x^5 - 5x^3 + 2x^2 - 10x + 4 = 4x^4 + 6x^3 - 11
Now, this is an equation that only depends on x.
We can simplify it to get:
3x^5 - 4x^4 - 11x^3 + 2x^2 - 10x + 15 = 0
That is the equation that we can solve using the given system of equations.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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Answer:
<em>B. The graph of g is the graph of f shifted 2 units down</em>
Step-by-step explanation:
<u>Graph of Functions</u>
We have two functions:
f(x)=3^x
g(x)=3^x-2
Since g(x)=f(x)-2 it will be represented as an identical graph as that for f(x), but vertically displaced 2 units down. Let's check it by plugging some points
f(0)=3^0=1
g(0)=3^0-2=-1
f(1)=3^1=3
g(1)=3^1-2=1
f(3)=3^3=27
g(3)=3^3-2=25
We can notice the values of g(x) are always 2 units below f(x), thus the correct answer is
B. The graph of g is the graph of f shifted 2 units down
I'm going to assume you just mean how do you write the ratio, in which case the answers vary
18:6
18 to 6
or
18/6
Answer:
The rate is 
cups per hour
Step-by-step explanation:
It took the faucet 1 1/2 hours, i.e 1.5 or 3/2 hours to fill 1/4 cup by leaking
We need to find the rate in terms of cups that can be filled by water in 1 hour.
Using unitary method:
If it takes 
h for 
cup;
then it will take 1 h for how many cups?
cups
Therefore, the rate is cups per hour
