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borishaifa [10]
3 years ago
6

How many feet tall is the streetlight

Mathematics
2 answers:
Feliz [49]3 years ago
4 0
12 feet apparently i knew this s/5= (st4)/12 s=20/7
Lorico [155]3 years ago
3 0
About 12 feet tall it depends but on math version it's 5 feet tall. I'm not really sure though.
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How do you do these two questions?
Mice21 [21]

Answer:

a) d²y/dx² = ½ x + y − ½

b) Relative minimum

Step-by-step explanation:

a) Take the derivative with respect to x.

dy/dx = ½ x + y − 1

d²y/dx² = ½ + dy/dx

d²y/dx² = ½ + (½ x + y − 1)

d²y/dx² = ½ x + y − ½

b) At (0, 1), the first and second derivatives are:

dy/dx = ½ (0) + (1) − 1

dy/dx = 0

d²y/dx² = ½ (0) + (1) − ½

d²y/dx² = ½

The first derivative is 0, and the second derivative is positive (concave up).  Therefore, the point is a relative minimum.

4 0
3 years ago
Which expression is equivalent to StartRoot 128 x Superscript 8 Baseline y cubed z Superscript 9 Baseline EndRoot? Assume y grea
zepelin [54]

The expression √(128x⁸y³z⁹) is equivalent to the expression 8x⁴yz⁴ √(2yz). Then the correct option is C.

The missing options are given below.

<h3>What is an equivalent expression?</h3>

The equivalent is the expressions that are in different forms but are equal to the same value.

The expression is given below.

⇒ √(128x⁸y³z⁹)

Then the expression is given below.

⇒ √[(64 × 2)(x⁴)²(y²y)(z⁸z)]

⇒ 8x⁴yz⁴ √(2yz)

Then the correct option is C.

More about the equivalent link is given below.

brainly.com/question/889935

#SPJ1

4 0
2 years ago
What is the side length of the eectagkes
dedylja [7]

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Step-by-step explanation:

<u>1. 5 in and 1/3 in</u>

Here,

Let\\l=5\\w=\frac{1}{3}\\Area=l*w\\=5*\frac{1}{3}\\=\frac{5}{3}\ in^2

<u>2. 5 in and 4/3 in</u>

Here,

l= 5\ in\\w=\frac{4}{3}\ in\\Area=l*w\\=5*\frac{4}{3}\\=\frac{20}{3}\ in^2

<u>3. 5/2 in and 4/3 in</u>

let\\l=\frac{5}{2}\\w=\frac{4}{3}\\Area= \frac{5}{2}*\frac{4}{3}\\=\frac{20}{6}=\frac{10}{3}\ in^2

<u>4. 7/6 in and 6/7 in</u>

<u>Let</u>

l=\frac{6}{7}\\w=\frac{7}{6}\\Area=l*w\\=\frac{6}{7}*\frac{7}{6}\\=1\ in^2

<u>Hence,</u>

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Keywords: Rectangle, Area

Learn more about rectangles at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

8 0
3 years ago
One side of a square is 4x, what is the area of this square?
Degger [83]

Answer:

16x^2

Step-by-step explanation:

To find the area of a square, we use the formula

A = s^2  where s is the side length

A = (4x)^2

A = 16x^2

3 0
3 years ago
Read 2 more answers
What is the solution to the equation 41/5 =15-(2x+3)
likoan [24]
\frac{41}{5}=15-(2x+3) \\\\ \frac{41}{5}=15-2x-3 \\\\ \frac{41}{5}=12^{(5}-2x^{(5} \\\\ 41=60-10x \\\\ 41-60=-10x \\\\ -19=-10x \\\\ 19=10x \\\\ \boxed{x=\frac{19}{10}}
4 0
3 years ago
Read 2 more answers
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