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Colt1911 [192]
3 years ago
12

HELP ME IN 10 MINUTES!!!! ASAP!!!!!!!!!!!! THX! NO FILES! Will give brainliest!

Mathematics
1 answer:
kotegsom [21]3 years ago
7 0

Answer:

Step-by-step explanation:

whats the question?

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---------------------------------------------</span>
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Explain why the quadratic relation y=2x^2+3x+5 would have no zeros
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Complete the square to rewrite the quadratic:

2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5

... = 2 (<em>x</em>² + 3/2 <em>x</em> + 9/16 - 9/16) + 5

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Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.

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3 years ago
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