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2 answers:
9514 1404 393
Answer:
a = 36
Step-by-step explanation:
A stationary point is where the function derivative is zero. Here, we have ...
y' = 2kx -16/x^2 = 0
For x = 2/3, this is ...
4/3k -16/(4/9) = 0
4/3k = 36
k = 27
Then the value of y at that point is ...
y = 27(2/3)^2 + 16/(2/3) = 12 +24 = 36
The stationary point of interest is (2/3, a) = (2/3, 36). a = 36.
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The answer is 5/2. The equation is already in point slope form. If you recall, the equation for point slope form is y-y1 = m(x-x1) where y1 and x1 are points on the graph, and m is the slope. In the given equation, m is 5/2 so we know it is the slope.
Alternatively, if you are not familiar with the point slope for equation, you can manipulate the equation to the form of y=mx+b where m is the slope and b is the constant. If you solve for y, you get y=5/2x-1 since 5/2 is in the place of m, we know 5/2 is the slope.
Alternatively, if you are not familiar with the point slope for equation, you can manipulate the equation to the form of y=mx+b where m is the slope and b is the constant. If you solve for y, you get y=5/2x-1 since 5/2 is in the place of m, we know 5/2 is the slope.