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never [62]
3 years ago
8

What is the perimeter of the rhombus below?

Mathematics
1 answer:
DiKsa [7]3 years ago
4 0

Answer:A

Step-by-step explanation:

from Pythagoras principle we get:

Hypotenuse=√(4^2+2^2)

Hypotenuse=√(4x4+2x2)

Hypotenuse=√(16+4)

Hypotenuse=√(20)

Hypotenuse=√(4x5)

Hypotenuse=√4 x √5

Hypotenuse=2 x √5

Hypotenuse=2√5

Perimeter=4 x hypotenuse

Perimeter=4 x 2√5

Perimeter=8√5

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Hey you ‼️ yeah I unfortunately need your help again these are hard:(
Helga [31]

Answer:

Step-by-step explanation:

The point of this question is to find out the point where two lines intersect. First we need to get the equation of those lines

Slope of line 1:

(Yb -Ya)/(Xb - Xa) =

(-10 - (-14))/(-1 - (-3)) =

4/2 =

2

Use that slope to find the Y-intercept of line 1

y = 2x + b

-14 = 2(-3) +b

-14 = -6 + b

-8 = b

Therefore Line 1 is:

y = 2x - 8

Slope of line 2

(11 - 13)/(-1 - (-3)) =

-2/2 =

-1

Y-intercept of line 2

y = -x + b

13 = -(-3) +b

13 = 3 + b

10 = b

Therefore line 2 is

y = -x + 10

Now we have 2 equations to solve for the coordinates x and y

y = 2x - 8

y = -x + 10

Substitute y out in one of the equations

2x - 8 = -x + 10

3x = 18

x = 6

Plug x into one of the equations

y = 2(6) - 8

y = 12 - 8

y = 4

Therefore the solution is:

x=6, y=4

8 0
3 years ago
Read 2 more answers
2/5 times ( -10)=?<br> ?=
Rudiy27

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Answer:

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