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zaharov [31]
3 years ago
8

9.Water flows'along a horizontal pipe of cross sectional area 48cm2 which has a constriction of

Physics
1 answer:
Kamila [148]3 years ago
3 0

Answer:

v₁ = 9 m/s

Explanation:

Here, we can use the continuity equation, as follows:

A_1v_1 = A_2v_2

where,

A₁ = Cross-sectional area of the wider section = 48 cm²

A₂ = Cross-sectional area of the constriction = 12 cm²

v₁ = speed of flow in wider section = ?

v₂ = speed flow in constriction = 36 m/s

Therefore,

(48\ cm^2)v_1 = (12\ cm^2)(36\ m/s)\\\\v_1 = \frac{(12\ cm^2)(36\ m/s)}{(48\ cm^2)} \\\\

<u>v₁ = 9 m/s</u>

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