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1 answer:
Answer:
1.
<u>An extraneous solution is a root of a transformed equation that is not a root of the original equation as it was excluded from the domain of the original equation.</u>
It emerges from the process of solving the problem as a equation.
2.I begin like:
The vertical asymptotes will occur at those values of x for which the denominator is equal to zero:
for example:
x² − 4=0
x²= 4
doing square root on both side
x = ±2
Thus, the graph will have vertical asymptotes at x = 2 and x = −2.
To find the horizontal asymptote, the degree of the numerator is one and the degree of the denominator is two.
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Answer:
S(-2, -3)
Step-by-step explanation:
Find the diagram attached below,=. Frim the diagram, the coordinate of R and T are (-5, 3) and (-1, -5) respectively. If the ratio of RS to ST is 3:1, the coordinate of S can be gotten using the midpoint segment formula as shown;
S(X, Y) = {(ax1+bx2/a+b), (ay1+by1/a+b)} where;
x1 = -5, y1 = 3, x2 = -1, y2 = -5, a = 3 and b =1
Substitute the values into the formula;
X = ax2+bx1/a+b
X = 3(-1)+1(-5)/3+1
X = -3-5/4
X = -8/4
X = -2
Similarly;
Y = ay2+by1/a+b
Y = 3(-5)+1(3)/3+1
Y = -15+3/4
Y = -12/4
Y = -3
Hence the coordinate of the point (X, Y) is (-2, -3)
