NO LINKS OR ANSWERING WHAT YOU DON'T KNOW. THIS NOT A TEST OR AN ASSESSMENT. PLEASE HELP ME WITH THESE MATH QUESTIONS FOR AN ASS
1 answer:
Answer:
1.
<u>An extraneous solution is a root of a transformed equation that is not a root of the original equation as it was excluded from the domain of the original equation.</u>
It emerges from the process of solving the problem as a equation.
2.I begin like:
The vertical asymptotes will occur at those values of x for which the denominator is equal to zero:
for example:
x² − 4=0
x²= 4
doing square root on both side
x = ±2
Thus, the graph will have vertical asymptotes at x = 2 and x = −2.
To find the horizontal asymptote, the degree of the numerator is one and the degree of the denominator is two.
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the answer to this is
Answer:
Step-by-step explanation:
This is a horizontally stretched ellipse. That means that the horizontal line which is represented by the x-axis is the longer one. The equation for this type of ellipse is
In an ellipse, the a value is ALWAYS bigger than the b value, and since the x-axis represents the longer axis, the a goes under the x-squared term.
To solve for the h, the k, the a, and the b, we simply have to do some counting. The center of the ellipse, the (h, k) our of equation, is sitting at (4, 6). Put them where they belong in the equation. The a axis (the horizontal one) is 8 units long, and the b axis (the vertical one) is 4 units long. Square both of them and put them where they belong in the equation:
There you go!