NO LINKS OR ANSWERING WHAT YOU DON'T KNOW. THIS NOT A TEST OR AN ASSESSMENT. PLEASE HELP ME WITH THESE MATH QUESTIONS FOR AN ASS
1 answer:
Answer:
1.
<u>An extraneous solution is a root of a transformed equation that is not a root of the original equation as it was excluded from the domain of the original equation.</u>
It emerges from the process of solving the problem as a equation.
2.I begin like:
The vertical asymptotes will occur at those values of x for which the denominator is equal to zero:
for example:
x² − 4=0
x²= 4
doing square root on both side
x = ±2
Thus, the graph will have vertical asymptotes at x = 2 and x = −2.
To find the horizontal asymptote, the degree of the numerator is one and the degree of the denominator is two.
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1. We are given:
The only a which squared gives you 64 is 8. The perimeter of an 8 by 8 square will be 32. Half of that is 16. Now, let's see what we can do. We can set up:
Obviously, each side length has to be 4. So, the area of this square will be 16 units².
2. Let n equal her son's age. So, her age right now will be (S = her age):
1 year ago it was:
We have 2 equations, let's substitute. We can rewrite this as:
Solve for n:
We know the value of n, which is her son's age. So, her son is 1/15 of a year old or about 24 days old.
The only a which squared gives you 64 is 8. The perimeter of an 8 by 8 square will be 32. Half of that is 16. Now, let's see what we can do. We can set up:
Obviously, each side length has to be 4. So, the area of this square will be 16 units².
2. Let n equal her son's age. So, her age right now will be (S = her age):
1 year ago it was:
We have 2 equations, let's substitute. We can rewrite this as:
Solve for n:
We know the value of n, which is her son's age. So, her son is 1/15 of a year old or about 24 days old.