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dedylja [7]
3 years ago
12

NO LINKS OR ANSWERING WHAT YOU DON'T KNOW. THIS NOT A TEST OR AN ASSESSMENT. PLEASE HELP ME WITH THESE MATH QUESTIONS FOR AN ASS

IGNMENT!!! Chapter 10 part 1
1. What is an extraneous solution and what type of functions might they occur in?

2. Given a vertical asymptote and horizontal asymptote, how would you begin to find an expression for a rational function?
Mathematics
1 answer:
liberstina [14]3 years ago
8 0

Answer:

1.

<u>An extraneous solution is a root of a transformed equation that is not a root of the original equation as it was excluded from the domain of the original equation.</u>

It emerges from the process of solving the problem as a equation.

2.I begin like:

The vertical asymptotes will occur at those values of x for which the denominator is equal to zero:

for example:

x² − 4=0

x²= 4

doing square root on both side

x = ±2

Thus, the graph will have vertical asymptotes at x = 2 and x = −2.

To find the horizontal asymptote, the degree of the numerator is one and the degree of the denominator is two.

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Identify the perimeter and area of a square with diagonal length 11in. Give your answer in simplest radical form. HELP PLEASE!!
Nataliya [291]

Answer:

  • Perimeter = 22*sqrt(2)
  • Area = 60.5 inches
  • D

Step-by-step explanation:

Remark

You need 2 facts.

  1. A square has 4 equal sides.
  2. It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.

That means you can use the Pythagorean Theorem.

If one side of a square is a then the 1 after it is a as well.

Formula

  • a^2 + a^2 = c^2
  • 2a^2 = c^2

Givens

  • c = 11

Solution

  • 2a^2 = 11^2
  • 2a^2 = 121                    Divide by 2
  • a^2 = 121/2                  Take the square root of both sides
  • sqrt(a^2) = sqr(121/2)    
  • a = 11/sqrt(2)                Rationalize the denominator
  • a = 11 * sqrt(2)/[sqrt(2) * sqrt(2)]
  • a = 11 * sqrt(2) / 2

<em><u>Perimeter</u></em>

P = 4s

  • P = 4*11*sqrt(2)/2
  • P = 44*sqrt(2)/2
  • P = 22*sqrt(2)

You don't need the area. The answer is D

<em><u>Area</u></em>

  • Area = s^2
  • Area = (11*sqrt(2)/2 ) ^2
  • Area = 121 * 2 / 4
  • Area = 60.5


8 0
3 years ago
Solve.<br> sec 315 degrees
densk [106]

Answer:

1.41

Step-by-step explanation:

5 0
3 years ago
Please help in really stuck ​
sattari [20]

\int\limits {\pi y^2} \, dy

y = 2 + x^6

y - 2 = x^6

x = (y - 2)^1/6

\pi \int\limits^3_2 {(y - 2)^{1/6}} \, dx

Well, solving this integral

\pi \int\limits^3_2 {(y - 2)^{1/6}} \, dx = 2,69279

6 0
3 years ago
How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have?
dem82 [27]
How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have? 

Answer: the third option (12 zeros..). 

Use ^ to denote an exponent.. 

f(x) = 3x^12 - 17x^8 + 11x^4 - 6x + 23.. 


We know from that fact that the number of zeros (real or complex) in a polynomial is the same as the degree of the polynomial.. 

The degree is the greatest/highest power of the terms, which in this case is 12 (since 12 is the greatest exponent..).. 

The degree is 12, thus it means there are 12 zero's.. 


Answer: the third option (12 zero's )...
3 0
3 years ago
Please and thank you for helping !
Paul [167]

Answer:

9 D and 10 B

Step-by-step explanation:

The conditional is what is next to IF and the hypothesis is what you expect in this case you expect it to be a whole number and a integer

5 0
3 years ago
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