Recall your d = rt, distance = rate * time.
b = speed rate of the boat.
c = speed rate of the current.
keeping in mind that, as the boat goes Upstream, against the current, it's speed is not "b", but is really " b - c ", because the current is subtracting speed from it.
likewise, when the boat is going Downstream, because is going with the current, is really going faster at " b + c ".

what is the speed of the boat? well, 61 + c = b.
Answer:
Circle requires ≈ 20 m of edging
Step-by-step explanation:
A = πR²
R = √(A/π)
C = 2πR = 2π√(A/π)
C = 2π√(30/π) = 19.41625... ≈ 20 m
square needs ≈ 22 m of edging
equilateral triangle needs ≈ 25 m of edging
Answer:
Step-by-step explanation:
5,9,11,(13,16),16,19,21
the mean(middle number) = (13 + 16) / 2 = 29/2 = 14.5
Q1 = (9 + 11) / 2 = 20/2 = 10
Q3 = (16 + 19) / 2 = 35/2 = 17.5
interquartile range (IQR) = Q3 - Q1 = 17.5 - 10 = 7.5 <==
(b^2+5)(−b^2+7)
Use the FOIL METHOD to expand.
-b^4 + 7b^2 - 5b^2 + 35
-b^4 + 2b^2 + 35
Did you follow?