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MaRussiya [10]
2 years ago
10

Which expression is equivalent to StartRoot 120 x EndRoot?.

Mathematics
1 answer:
Irina-Kira [14]2 years ago
5 0

Here for 120, the expression for the start root and end root is given  

\sqrt{120} =2\sqrt{30}

<h3>What will be the expression for start root and enroot of 120?</h3>

Here we need to find \sqrt{120}

By simplifying the given expression, we get:

120=2\times2\times2\times3\times5

120=(2^{2} )\times3\times5

by taking square roots on both sides we get

\sqrt{120} =2\sqrt{30}

Thus for 120, the expression for the start root and end root is given  \sqrt{120} =2\sqrt{30}

To know more about the Square roots follow

brainly.com/question/124481

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Sixty percent of the runners who ran the marathon finished the race. If fifteen runners finished, then how many runners ran in t
ZanzabumX [31]

Let they be x

\\ \rm\Rrightarrow 60\%\: of\:x=15

\\ \rm\Rrightarrow \dfrac{3}{5}x=15

\\ \rm\Rrightarrow x=15\times \dfrac{5}{3}

\\ \rm\Rrightarrow x=5(5)

\\ \rm\Rrightarrow x=25

4 0
2 years ago
the sport field at patton elementryschool is shaped like a rectangle . the field is 72 yard lobg and 46 yardwide. what isthe are
valina [46]
Length x width will give you area so...

72 x 46 = 3,312 yards is the area
6 0
3 years ago
A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a
Temka [501]
K · ( 0, 0 ) = ( 0 , 0 )
k · ( 0 , 4 ) = ( 0 , 10 )
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8 0
3 years ago
Define product. give an example of two whole number factors with a product of 9
Kryger [21]

Answer:

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3 x 3=9

Step-by-step explanation:

8 0
3 years ago
I need help fast please I don’t understand this and I’ve been struggling for a while. Can I get a brain list please or a tutor t
solong [7]

Answer:

4 √6

Step-by-step explanation:

We have a few right triangles. We know that a²+b²=c², with c being the side opposite the right angle. Representing the side without a value as z, we have:

m²+z² = (8+4)² = 12²

4²+n²=z²

8²+n²=m²

We have 3 equations with 3 unknown variables, so this should be solvable. One way to find a solution is to put everything in terms of m and go from there. First, we can take n out of the equations entirely, removing one variable. We can do this by solving for it in terms of z and plugging that into the third equation, removing a variable as well as an equation.

4²+n²=z²

subtract 4²=16 from both sides

z²-16 = n²

plug that into the third equation

64 + z² - 16 = m²

48 + z² = m²

subtract 48 from both sides to solve for z²

z² = m² - 48

plug that into the first equation

m² + m² - 48 = 144

2m² - 48 = 144

add 48 to both sides to isolate the m² and its coefficient

192 = 2m²

divide both sides by 2 to isolate the m²

96 = m²

square root both sides to solve for m

√96 = m

we know that 96 = 16 * 6, and 16 = 4², so

m = √96 = √(4²*6) = 4 √6

5 0
2 years ago
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