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Paraphin [41]
3 years ago
12

The Leibnitz notation for the chain rule is

Mathematics
1 answer:
tankabanditka [31]3 years ago
6 0

For this derivative, you could set

\boxed{u = x^2 - 4x}

Then

y = \sin(x^2-4x) = \sin(u)

so that

\boxed{\dfrac{\mathrm dy}{\mathrm du} = \cos(u)}

and

\boxed{\dfrac{\mathrm du}{\mathrm dx} = 2x - 4}

Then the chain rule gives

\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm dy}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \cos(u)(2x-4) \\\\ \boxed{\dfrac{\mathrm dy}{\mathrm dx} = (2x-4)\cos(x^2-4x)}

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FInd the GCF of the numbers using prime factorizations.
lesya [120]

Answer:

GCF(330, 75, 450, 225) = 15

Steps:

Prime factorization of the numbers:

330 = 2 × 3 × 5 × 11

75 = 3 × 5 × 5

450 = 2 × 3 × 3 × 5 × 5

225 = 3 × 3 × 5 × 5

GCF(330, 75, 450, 225)

= 3 × 5

= 15

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3 years ago
Which of the following are equivalent
Nataly_w [17]
Where’s the question?
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The swimming pool is opening hours a day the pool manager must divide pool time equally among five groups camp; camp swim team,
ale4655 [162]

Answer:

1.6 hours

Step-by-step explanation:

Number of opening hours a day = 8

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Dividing the number of opening. Hours equally among the 5 groups :

8 hours / 5

= 1.6 hours per group per day

4 0
3 years ago
Question 1
PilotLPTM [1.2K]

The true statement about why the Fibonacci sequence is recursively defined is (c) The Fibonacci sequence is recursively-defined because you must know the values of the two previous terms in order to find the value of the next term

<h3>How to determine the true statement</h3>

With an exception to the first two terms, each term of the Fibonacci sequence is the sum of the two previous terms

This means that,

The Fibonacci sequence cannot be defined explicitly, because the two previous terms can not be determined by a direct formula

Hence, the true statement about why the Fibonacci sequence is recursively defined is (c)

Read more about the Fibonacci sequence at:

brainly.com/question/16934596

8 0
2 years ago
How to subtract with renaming fractions
givi [52]
<span>1.Rename with common denominators.
2.Regroup the first fraction.
3.Subtract the whole numbers and numerators.
<span>4.Simplify (if necessary)</span></span>
3 0
3 years ago
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